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As Student Council President, Marcy organized a school-wide scavenger hunt. She hid 88 goody bags, 66 of which were hidden in the main office. If 55 goody bags were randomly discovered during first period, what is the probability that all of them were hidden in the main office?\newlineWrite your answer as a decimal rounded to four decimal places._____

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Q. As Student Council President, Marcy organized a school-wide scavenger hunt. She hid 88 goody bags, 66 of which were hidden in the main office. If 55 goody bags were randomly discovered during first period, what is the probability that all of them were hidden in the main office?\newlineWrite your answer as a decimal rounded to four decimal places._____
  1. Total Goody Bags: Total number of goody bags: 88\newlineGoody bags to be found: 55\newlineCalculate total possible outcomes using combinations.\newlineTotal outcomes: (85)\binom{8}{5}
  2. Calculate Total Outcomes: Find the value of (85)\binom{8}{5}. (85)=8!5!(85)!=8!5!3!=8×7×6×5!5!×3×2×1=56\binom{8}{5} = \frac{8!}{5!(8-5)!} =\frac{8!}{5!3!} =\frac{8 \times 7 \times 6 \times 5!}{5! \times 3 \times 2 \times 1} = 56
  3. Favorable Outcomes from Main Office: Number of goody bags in the main office: 66\newlineGoody bags to be found from the main office: 55\newlineCalculate favorable outcomes using combinations.\newlineFavorable outcomes: 6C5{}_{6}C_{5}
  4. Calculate Probability: Find the value of (65)\binom{6}{5}.\newline(65)=6!5!(65)!=6!5!1!=6×5!5!×1=6\binom{6}{5} = \frac{6!}{5!(6-5)!} =\frac{6!}{5!1!} = \frac{6 \times 5!}{5! \times 1} = 6
  5. Calculate Probability: Find the value of 6C5_6C_5. 6C5=6!5!(65)!=6!5!1!=6×5!5!×1=6 _6C_5 = \frac{6!}{5!(6-5)!} =\frac{6!}{5!1!} = \frac{6 \times 5!}{5! \times 1} = 6Calculate the probability. Probability = Favorable outcomes / Total possible outcomes =656=0.1071= \frac{6}{56} = 0.1071 when rounded to four decimal places.

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