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arccos(theta)=((-17)/(sqrt38×3))

arccos⁡(θ)=(−1738×3) \arccos (\theta)=\left(\frac{-17}{\sqrt{38} \times 3}\right)

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Csc, sec, and cot of special anglesright chevron icon

Full solution

Q. arccos⁡(θ)=(−1738×3) \arccos (\theta)=\left(\frac{-17}{\sqrt{38} \times 3}\right)
  1. Find Cosine Value: Find the value of the cosine that corresponds to the given arccos value.\newlinecos⁡(arccos⁡(θ))=θ\cos(\arccos(\theta)) = \theta\newlineθ=−1738×3\theta = \frac{-17}{\sqrt{38}\times3}
  2. Simplify Denominator: Simplify the denominator of the fraction. 38×3=38×32=38×9=342\sqrt{38}\times3 = \sqrt{38}\times\sqrt{3^2} = \sqrt{38\times9} = \sqrt{342} θ=−17342\theta = \frac{-17}{\sqrt{342}}
  3. Rationalize Denominator: Rationalize the denominator by multiplying the numerator and denominator by 342\sqrt{342}.θ=−17×342342×342\theta = \frac{-17\times\sqrt{342}}{\sqrt{342}\times\sqrt{342}}θ=−17×342342\theta = \frac{-17\times\sqrt{342}}{342}

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