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ara
1
1
1
-Soskion
2
2
2
Cilsulator A systern of equations is shom \left\{\begin{array}{l}2x+2y=17\4x-y=25\end{array}\right. Enter your answer in the box.
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Math Problems
Grade 8
Write an equation word problem
Full solution
Q.
ara
1
1
1
-Soskion
2
2
2
Cilsulator A systern of equations is shom \left\{\begin{array}{l}2x+2y=17\4x-y=25\end{array}\right. Enter your answer in the box.
Write Equations:
Step
1
1
1
: Write down the system of equations.
\newline
Equation 1:
2
x
+
2
y
=
17
\text{Equation 1: } 2x + 2y = 17
Equation 1:
2
x
+
2
y
=
17
\newline
Equation 2:
4
x
−
y
=
25
\text{Equation 2: } 4x - y = 25
Equation 2:
4
x
−
y
=
25
Simplify Equation
1
1
1
:
Step
2
2
2
: Simplify Equation
1
1
1
by dividing all terms by
2
2
2
.
\newline
x
+
y
=
17
2
x + y = \frac{17}{2}
x
+
y
=
2
17
Solve for y:
Step
3
3
3
: Solve for y from Equation
2
2
2
.
\newline
y
=
4
x
−
25
y = 4x - 25
y
=
4
x
−
25
Substitute and Simplify:
Step
4
4
4
: Substitute y from Equation
3
3
3
into the simplified Equation
1
1
1
.
\newline
x
+
(
4
x
−
25
)
=
17
2
x + (4x - 25) = \frac{17}{2}
x
+
(
4
x
−
25
)
=
2
17
\newline
5
x
−
25
=
17
2
5x - 25 = \frac{17}{2}
5
x
−
25
=
2
17
Solve for x:
Step
5
5
5
: Solve for x.
\newline
5
x
=
17
2
+
25
5x = \frac{17}{2} + 25
5
x
=
2
17
+
25
\newline
5
x
=
17
2
+
50
2
5x = \frac{17}{2} + \frac{50}{2}
5
x
=
2
17
+
2
50
\newline
5
x
=
67
2
5x = \frac{67}{2}
5
x
=
2
67
\newline
x
=
67
10
x = \frac{67}{10}
x
=
10
67
Substitute for y:
Step
6
6
6
: Substitute x back into Equation
3
3
3
to find y.
\newline
y
=
4
(
67
10
)
−
25
y = 4(\frac{67}{10}) - 25
y
=
4
(
10
67
)
−
25
\newline
y
=
268
10
−
25
y = \frac{268}{10} - 25
y
=
10
268
−
25
\newline
y
=
26.8
−
25
y = 26.8 - 25
y
=
26.8
−
25
\newline
y
=
1.8
y = 1.8
y
=
1.8
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