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Approximate the area between 
h(x) and the 
x-axis from 
x=-2 to 
x=4 using a right Riemann sum with 3 equal subdivisions.

R(3)=

◻ units 
^(2).
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Approximate the area between h(x) h(x) and the x x -axis from x=2 x=-2 to x=4 x=4 using a right Riemann sum with 33 equal subdivisions.\newlineR(3)= R(3)= \newline \square units 2 ^{2} .\newlineShow Calculator

Full solution

Q. Approximate the area between h(x) h(x) and the x x -axis from x=2 x=-2 to x=4 x=4 using a right Riemann sum with 33 equal subdivisions.\newlineR(3)= R(3)= \newline \square units 2 ^{2} .\newlineShow Calculator
  1. Calculate Subdivision Width: First, we need to find the width of each subdivision. The interval from x=2x=-2 to x=4x=4 is 66 units wide. Since we're using 33 equal subdivisions, each subdivision will be 63=2\frac{6}{3} = 2 units wide.
  2. Find Right Endpoints: Next, we calculate the xx-values at the right endpoints of each subdivision. Starting from x=2x=-2, we add the width of each subdivision to get the right endpoints: 2+2=0-2+2=0, 0+2=20+2=2, and 2+2=42+2=4.
  3. Evaluate Function h(x)h(x): Now we need to know the function h(x)h(x) to evaluate it at these right endpoints. Since the problem doesn't provide h(x)h(x), we can't proceed with the calculation. We need the function to approximate the area.

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