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answer

y=3x+6
Problem





X

Y


1
80


2
130


3
180


4
230


5
280




What equation represents the linear relationship shown in the table?
Mrs. Casias Math 2020 
*

answer\newliney=3x+6 y=3 x+6 \newlineProblem\newline\begin{tabular}{|c|c|}\newline\hlineX X & Y Y \\\newline\hline 11 & 8080 \\\newline\hline 22 & 130130 \\\newline\hline 33 & 180180 \\\newline\hline 44 & 230230 \\\newline\hline 55 & 280280 \\\newline\hline\newline\end{tabular}\newlineWhat equation represents the linear relationship shown in the table?\newlineMrs. Casias Math 20202020 \cdot

Full solution

Q. answer\newliney=3x+6 y=3 x+6 \newlineProblem\newline\begin{tabular}{|c|c|}\newline\hlineX X & Y Y \\\newline\hline 11 & 8080 \\\newline\hline 22 & 130130 \\\newline\hline 33 & 180180 \\\newline\hline 44 & 230230 \\\newline\hline 55 & 280280 \\\newline\hline\newline\end{tabular}\newlineWhat equation represents the linear relationship shown in the table?\newlineMrs. Casias Math 20202020 \cdot
  1. Calculate y differences: First, let's look at the differences in yy when xx increases by 11. From x=1x=1 to x=2x=2, yy increases by 5050 (13080130-80). From x=2x=2 to x=3x=3, yy increases by 5050 (xx22). This pattern continues for all xx values in the table.
  2. Identify linear relationship: Since the increase in yy is consistent as xx increases, the relationship is linear and the slope (mm) is 5050.
  3. Find y-intercept: Now, let's find the y-intercept bb by looking at the table.\newlineWhen x=1x=1, y=80y=80.\newlineUsing the slope we found, we can write the equation as y=mx+by=mx+b and plug in x=1x=1, y=80y=80, and m=50m=50.\newline80=50(1)+b80 = 50(1) + b
  4. Solve for b: Solving for b, we get b=8050b = 80 - 50.\newlineb=30b = 30
  5. Final equation: So the equation of the line is y=50x+30y = 50x + 30.

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