Answer two questions about Systems A and B :\begin{tabular}{cc} System A & System B \\ \left\{\begin{array}{l}-2 x+5 y=10 \\\(\newline-3 x+9 y=6\end{array}\right. \) & \left\{\begin{array}{l}-3 x+9 y=6 \\\(\newline-2 x+5 y=10\end{array}\right. \)\end{tabular}1) How can we get System B from System A ?Choose 1 answer:(A) Replace one equation with a multiple of the(B) Replace one equation with a multiple of itseDo 5 problems
Q. Answer two questions about Systems A and B :\begin{tabular}{cc} System A & System B \\ \left\{\begin{array}{l}-2 x+5 y=10 \\\(\newline-3 x+9 y=6\end{array}\right. \) & \left\{\begin{array}{l}-3 x+9 y=6 \\\(\newline-2 x+5 y=10\end{array}\right. \)\end{tabular}1) How can we get System B from System A ?Choose 1 answer:(A) Replace one equation with a multiple of the(B) Replace one equation with a multiple of itseDo 5 problems
Look at Systems: Look at System A and System B, they have the same equations but in reverse order.
Switch Equations: To get System B from System A, we just need to switch the order of the two equations.
Answer Explanation: So, the answer is (A) Replace one equation with a multiple of the other, but that's not what we did. We just switched them. Oops, that's not right.
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