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annum for 4 years. Find the markup of the bank.
3. Naseem receives a profit of Rs 27,000 at the rate of 
12% per yeaf for 3 years. Find his original investment.
A. At what annual rate percent would 
Rs68,000 amount to

annum for 44 years. Find the markup of the bank.\newline33. Naseem receives a profit of Rs 2727,000000 at the rate of 12% 12 \% per yeaf for 33 years. Find his original investment.\newlineA. At what annual rate percent would Rs68,000 \mathrm{Rs} 68,000 amount to

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Q. annum for 44 years. Find the markup of the bank.\newline33. Naseem receives a profit of Rs 2727,000000 at the rate of 12% 12 \% per yeaf for 33 years. Find his original investment.\newlineA. At what annual rate percent would Rs68,000 \mathrm{Rs} 68,000 amount to
  1. Identify values: Initial investment = $11100\$11100, Yearly deposit = $100\$100, Total years = 55, Final balance = $16100\$16100. Identify the values of AA, PP, nn, tt, P0P_0. A=16100A = 16100, $100\$10000, $100\$10011 (compounded annually), $100\$10022, $100\$10033.
  2. Use compound interest formula: Use the compound interest formula for an investment with annual deposits:\newlineA=P(1+rn)nt+P0×[(1+rn)nt1]/(rn)A = P(1 + \frac{r}{n})^{nt} + P_0 \times \left[\left(1 + \frac{r}{n}\right)^{nt} - 1\right]/\left(\frac{r}{n}\right)\newlineSubstitute the known values into the formula.\newline16100=11100(1+r)5+100×[(1+r)51]/r16100 = 11100(1 + r)^5 + 100 \times \left[(1 + r)^5 - 1\right]/r
  3. Simplify the equation: Simplify the equation:\newline16100=11100(1+r)5+100[(1+r)51]/r16100 = 11100(1 + r)^5 + 100\left[(1 + r)^5 - 1\right]/r\newlineThis is a complex equation that typically requires numerical methods or trial and error to solve for rr.
  4. Trial and error method: Assuming a trial and error method or using a calculator to solve for rr: After several attempts, we find that r0.08r \approx 0.08 or 8%8\% (This is an approximation; the exact rate might differ slightly).
  5. Calculate interest earned: Calculate the interest earned:\newlineInterest = Final balance - (Initial investment + Total deposits)\newlineInterest = 16100(11100+5×100)16100 - (11100 + 5\times100)\newlineInterest = 16100(11100+500)16100 - (11100 + 500)\newlineInterest = 161001160016100 - 11600\newlineInterest = 45004500

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