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An Osmium block has a density of
22.59g//cm^(3) and a mass of 420 grams. What is the volume of the block?
Round answer to the nearest hundredth.
The volume of the Osmium block is type your answer...
cm^(3)

An Osmium block has a density of $22.59 \mathrm{~g} / \mathrm{cm}^{3}$ and a mass of $420$ grams. What is the volume of the block? $\newline$ Round answer to the nearest hundredth. $\newline$ The volume of the Osmium block is type your answer... $\mathrm{cm}^{3}$

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Volume of cylinders

Full solution

Q. An Osmium block has a density of

22.59 \mathrm{~g} / \mathrm{cm}^{3}

and a mass of

420

grams. What is the volume of the block?

\newline

Round answer to the nearest hundredth.

\newline

The volume of the Osmium block is type your answer...

\mathrm{cm}^{3}

Density formula: Density formula: $\text{Density} = \frac{\text{Mass}}{\text{Volume}}$ . We need to find the $\text{Volume}$ , so rearrange the formula to $\text{Volume} = \frac{\text{Mass}}{\text{Density}}$ .
Plug in values: Plug in the values: $\text{Volume} = \frac{420 \, \text{grams}}{22.59 \, \text{g/cm}^3}$ .
Do the division: Do the division: Volume $\approx \frac{420}{22.59}$ .
Calculate result: Calculate the result: Volume $\approx 18.588 \, \text{cm}^3$ (before rounding).
Round the answer: Round the answer to the nearest hundredth: Volume $\approx 18.59 \, \text{cm}^3$ .

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