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An object is attached to a coiled spring. The object begins at its rest position at 
t=0 seconds. It is then propelled downward. Write an equation for the distance of the object from its rest position after 
t seconds, if the amplitude is 2 , inches and the period is 3.5 seconds.
The equation for the distance 
d of the object from its rest position is 
◻.
(Type an exact answer, using 
pi as needed. Use integers or fractions for any numbers in the equation.)

An object is attached to a coiled spring. The object begins at its rest position at t=0 t=0 seconds. It is then propelled downward. Write an equation for the distance of the object from its rest position after t t seconds, if the amplitude is 22 , inches and the period is 33.55 seconds.\newlineThe equation for the distance d \mathrm{d} of the object from its rest position is \square .\newline(Type an exact answer, using π \pi as needed. Use integers or fractions for any numbers in the equation.)

Full solution

Q. An object is attached to a coiled spring. The object begins at its rest position at t=0 t=0 seconds. It is then propelled downward. Write an equation for the distance of the object from its rest position after t t seconds, if the amplitude is 22 , inches and the period is 33.55 seconds.\newlineThe equation for the distance d \mathrm{d} of the object from its rest position is \square .\newline(Type an exact answer, using π \pi as needed. Use integers or fractions for any numbers in the equation.)
  1. Write Equation: To write the equation for the distance of the object from its rest position, we need to use the formula for simple harmonic motion, which is d(t)=Acos(2πt/T)d(t) = A \cdot \cos(2 \cdot \pi \cdot t / T), where AA is the amplitude and TT is the period.
  2. Substitute Amplitude: The amplitude AA is given as 22 inches, so we will substitute A=2A = 2 into the equation.
  3. Substitute Period: The period TT is given as 3.53.5 seconds, so we will substitute T=3.5T = 3.5 into the equation.
  4. Substitute Values: Now we substitute the values into the equation: d(t)=2cos(2πt/3.5)d(t) = 2 \cdot \cos(2 \cdot \pi \cdot t / 3.5).
  5. Calculate Coefficient: We can simplify the equation by calculating the coefficient of tt inside the cosine function. The coefficient is 2×π/3.52 \times \pi / 3.5.
  6. Simplify Coefficient: The simplified coefficient is (2×π)/3.5(2 \times \pi) / 3.5, which we can leave in terms of π\pi for an exact answer.
  7. Final Equation: The final equation for the distance dd of the object from its rest position after tt seconds is d(t)=2cos(2π3.5t)d(t) = 2 \cdot \cos\left(\frac{2 \cdot \pi}{3.5} \cdot t\right).

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