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An inverse variation includes the points (4,3)(4,\,3) and (2,n)(2,\,n). Find nn. \newlineWrite and solve an inverse variation equation to find the answer.\newlinen=____n = \,\_\_\_\_

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Q. An inverse variation includes the points (4,3)(4,\,3) and (2,n)(2,\,n). Find nn. \newlineWrite and solve an inverse variation equation to find the answer.\newlinen=____n = \,\_\_\_\_
  1. Identify general form: Given that the relationship between the variables is an inverse variation.\newlineIdentify the general form of inverse variation.\newlineInverse variation: y=kxy = \frac{k}{x}
  2. Substitute point (4,3)(4, 3): We know that the point (4,3)(4, 3) lies on the inverse variation curve.\newlineSubstitute x=4x = 4 and y=3y = 3 into the inverse variation equation y=kxy = \frac{k}{x} to find the constant of variation kk.\newline3=k43 = \frac{k}{4}
  3. Solve for constant: Solve for kk by multiplying both sides of the equation by 44.3×4=k3 \times 4 = k12=k12 = kNow we have found the constant of variation kk.
  4. Write inverse variation equation: Write the inverse variation equation using the constant of variation kk we found.\newlineSubstitute k=12k = 12 into y=kxy = \frac{k}{x}.\newlineThe inverse variation equation is y=12xy = \frac{12}{x}.
  5. Find nn for x=2x = 2: Use the inverse variation equation to find nn when x=2x = 2. Substitute x=2x = 2 into y=12xy = \frac{12}{x}. n=122n = \frac{12}{2} n=6n = 6

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