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An inverse variation includes the points (25,3)(25,\,3) and (5,n)(5,\,n). Find nn. \newlineWrite and solve an inverse variation equation to find the answer.\newlinen=____n = \,\_\_\_\_

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Q. An inverse variation includes the points (25,3)(25,\,3) and (5,n)(5,\,n). Find nn. \newlineWrite and solve an inverse variation equation to find the answer.\newlinen=____n = \,\_\_\_\_
  1. Identify Inverse Variation: Inverse variation means y=kxy = \frac{k}{x}. We got two points, (25,3)(25, 3) and (5,n)(5, n), so let's find kk first using the first point.
  2. Find kk using (25,3)(25, 3): Substitute x=25x = 25 and y=3y = 3 into y=kxy = \frac{k}{x} to find kk.\newline3=k253 = \frac{k}{25}
  3. Calculate kk: Multiply both sides by 2525 to solve for kk.3×25=k3 \times 25 = kk=75k = 75
  4. Find nn using (5,n)(5, n): Now we know k=75k = 75, we can use the second point (5,n)(5, n) to find nn.
  5. Find nn using (5,n)(5, n): Now we know k=75k = 75, we can use the second point (5,n)(5, n) to find nn.Substitute x=5x = 5 and k=75k = 75 into y=kxy = \frac{k}{x} to find nn.n=755n = \frac{75}{5}n=15n = 15

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