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An inverse variation includes the points (2, 4)(2,\ 4) and (1, n)(1,\ n). Find nn. \newlineWrite and solve an inverse variation equation to find the answer.\newlinenn = _______

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Q. An inverse variation includes the points (2, 4)(2,\ 4) and (1, n)(1,\ n). Find nn. \newlineWrite and solve an inverse variation equation to find the answer.\newlinenn = _______
  1. Identify general form of inverse variation: Given that there is an inverse variation that includes the points (2,4)(2, 4) and (1,n)(1, n). Identify the general form of inverse variation. In inverse variation, the product of the two variables is constant. Inverse variation: y=kxy = \frac{k}{x} where kk is the constant of variation.
  2. Find constant of variation: We know that the point (2,4)(2, 4) lies on the inverse variation curve.\newlineUse the point to find the constant of variation kk.\newlineSubstitute 22 for xx and 44 for yy in y=k/xy = k / x.\newline4=k/24 = k / 2
  3. Solve for kk: Solve the equation to find the value of kk. To isolate kk, multiply both sides by 22. 4×2=(k/2)×24 \times 2 = (k / 2) \times 2 8=k8 = k Now we have found the constant of variation kk.
  4. Find nn value: Use the constant of variation kk to find nn when x=1x = 1. The inverse variation equation is y=kxy = \frac{k}{x}. Substitute k=8k = 8 and x=1x = 1 into the equation. y=81y = \frac{8}{1} y=8y = 8 So, n=8n = 8.

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