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An inverse variation includes the points (2,3)(2,\,3) and (1,n)(1,\,n). Find nn. \newlineWrite and solve an inverse variation equation to find the answer.\newlinen=____n = \,\_\_\_\_

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Q. An inverse variation includes the points (2,3)(2,\,3) and (1,n)(1,\,n). Find nn. \newlineWrite and solve an inverse variation equation to find the answer.\newlinen=____n = \,\_\_\_\_
  1. Identify General Form: Given that there is an inverse variation between two variables.\newlineIdentify the general form of inverse variation.\newlineIn inverse variation, one variable is directly proportional to the reciprocal of the other.\newlineInverse variation: y=kxy = \frac{k}{x}
  2. Find Constant of Variation: We know that the points (2,3)(2, 3) are part of the inverse variation.\newlineUse the given point to find the constant of variation kk.\newlineSubstitute 22 for xx and 33 for yy in y=kxy = \frac{k}{x}.\newline3=k23 = \frac{k}{2}
  3. Solve for k: Solve the equation to find the value of kk. To isolate kk, multiply both sides by 22. 3×2=(k/2)×23 \times 2 = (k / 2) \times 2 6=k6 = k
  4. Write Inverse Variation Equation: We have found that k=6k = 6.\newlineWrite the inverse variation equation with the found value of kk.\newlineSubstitute k=6k = 6 into y=kxy = \frac{k}{x}.\newliney=6xy = \frac{6}{x}
  5. Find nn: Use the inverse variation equation to find nn when x=1x = 1. Substitute 11 for xx in y=6xy = \frac{6}{x}. n=61n = \frac{6}{1} n=6n = 6

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