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An English teacher gave his class a choice of 88 books to read, 66 of which are contemporary novels. If a student randomly picks 44 books, what is the probability that all of them are contemporary novels? Write your answer as a decimal rounded to four decimal places. ____

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Q. An English teacher gave his class a choice of 88 books to read, 66 of which are contemporary novels. If a student randomly picks 44 books, what is the probability that all of them are contemporary novels? Write your answer as a decimal rounded to four decimal places. ____
  1. Total Books and Choices: Total number of books: 88 Books to be chosen: 44 Calculate total possible outcomes using combinations. Total outcomes: 8C4_{8}C_{4}
  2. Calculate Total Outcomes: Find the value of (84)\binom{8}{4}. (84)=8!4!(84)!=8!4!4!=8×7×6×54×3×2×1=70\binom{8}{4} = \frac{8!}{4!(8-4)!} = \frac{8!}{4!4!} = \frac{8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 1} = 70
  3. Calculate Favorable Outcomes: Number of contemporary novels: 66 Books to be chosen that are contemporary novels: 44 Calculate favorable outcomes using combinations. Favorable outcomes: 6C4_{6}C_{4}
  4. Find Probability: Find the value of 6C4_6C_4. 6C4=6!4!(64)!=6!4!2!=6×52×1=15 _6C_4 = \frac{6!}{4!(6-4)!} = \frac{6!}{4!2!} = \frac{6 \times 5}{2 \times 1} = 15
  5. Find Probability: Find the value of (64)\binom{6}{4}.(64)=6!4!(64)!=6!4!2!=6×52×1=15\binom{6}{4} = \frac{6!}{4!(6-4)!} = \frac{6!}{4!2!} = \frac{6 \times 5}{2 \times 1} = 15Calculate the probability that all 44 books are contemporary novels.Probability=Favorable outcomesTotal possible outcomes=15700.2143\text{Probability} = \frac{\text{Favorable outcomes}}{\text{Total possible outcomes}} = \frac{15}{70} \approx 0.2143

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