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An elevator descends into a mine shaft at the rate of
6m//min. If the descent starts from
10m above the ground level, how long will it take to reach
-350m.

$7$ . An elevator descends into a mine shaft at the rate of $6 \mathrm{~m} / \mathrm{min}$ . If the descent starts from $10 \mathrm{~m}$ above the ground level, how long will it take to reach $-350 \mathrm{~m}$ .

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Add and subtract integers: word problems

Full solution

Q.

7

. An elevator descends into a mine shaft at the rate of

6 \mathrm{~m} / \mathrm{min}

. If the descent starts from

10 \mathrm{~m}

above the ground level, how long will it take to reach

-350 \mathrm{~m}

.

Calculate total distance: Calculate the total distance the elevator needs to descend. It starts from $10\,\text{m}$ above ground and goes down to $-350\,\text{m}$ . $\newline$ Total distance = $(-350\,\text{m}) - (10\,\text{m}) = -360\,\text{m}$
Divide by descent rate: Since the elevator descends at a rate of $6\,\text{m/min}$ , divide the total distance by the rate to find the time. $\newline$ Time $= \frac{\text{Total distance}}{\text{Rate}}$ $\newline$ Time $= \frac{-360\,\text{m}}{6\,\text{m/min}}$
Calculate time: Perform the division to calculate the time. $\newline$ Time = $-360m / 6m/min = -60$ min

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