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An angle measures 120.6120.6^\circ less than the measure of its supplementary angle. What is the measure of each angle?

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Q. An angle measures 120.6120.6^\circ less than the measure of its supplementary angle. What is the measure of each angle?
  1. Define Angles: Let's denote the smaller angle as AA and its supplementary angle as BB. We know that the sum of supplementary angles is 180°180°. The problem states that angle AA is 120.6°120.6° less than angle BB. We can set up the following equation:\newlineA+B=180°A + B = 180° (since they are supplementary angles)\newlineA=B120.6°A = B - 120.6° (since AA is 120.6°120.6° less than BB)
  2. Set Up Equation: Now we can substitute the expression for AA into the first equation: (B120.6°)+B=180°(B - 120.6°) + B = 180°
  3. Solve for B: Combine like terms to solve for B:\newline2B120.6°=180°2B - 120.6° = 180°\newline2B=180°+120.6°2B = 180° + 120.6°\newline2B=300.6°2B = 300.6°
  4. Find Angle B: Divide both sides by 22 to find the measure of angle B:\newlineB=300.6°÷2B = 300.6° \div 2\newlineB=150.3°B = 150.3°
  5. Find Angle A: Now that we have the measure of angle B, we can find the measure of angle A by subtracting 120.6120.6^\circ from B:\newlineA=B120.6A = B - 120.6^\circ\newlineA=150.3120.6A = 150.3^\circ - 120.6^\circ\newlineA=29.7A = 29.7^\circ

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