Amy used her first $2$ tokens at Glimmer Arcade to play a game of Roll-and-Score. Then she played her favorite game, Balloon Bouncer, over and over until she ran out of tokens. Balloon Bouncer costs $3$ tokens per game, and Amy started with a bucket of $35$ game tokens. $\newline$ Which equation can Amy use to find how many games of Balloon Bouncer, $g$ , she played? $\newline$ Choices: $\newline$ (A) $2g + 3 = 35$ $\newline$ (B) $3g + 2 = 35$ $\newline$ (C) $3(g + 2) = 35$ $\newline$ (D) $2(g + 3) = 35$ $\newline$ How many games of Balloon Bouncer did Amy play? $\newline$ ____ games

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Grade 7

Solve two-step equations: word problems

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Q. Amy used her first

2

tokens at Glimmer Arcade to play a game of Roll-and-Score. Then she played her favorite game, Balloon Bouncer, over and over until she ran out of tokens. Balloon Bouncer costs

3

tokens per game, and Amy started with a bucket of

35

game tokens.

\newline

Which equation can Amy use to find how many games of Balloon Bouncer,

g

, she played?

\newline

Choices:

\newline

(A)

2g + 3 = 35

\newline

(B)

3g + 2 = 35

\newline

(C)

3(g + 2) = 35

\newline

(D)

2(g + 3) = 35

\newline

How many games of Balloon Bouncer did Amy play?

\newline

____ games

Calculate Initial Tokens: Amy used $2$ tokens initially for Roll-and-Score. She had $35$ tokens total. So, tokens left for Balloon Bouncer = $35 - 2 = 33$ tokens.
Calculate Number of Games: Each game of Balloon Bouncer costs $3$ tokens. To find the number of games she played, we divide the tokens used for Balloon Bouncer by the cost per game. Number of games, $g = \frac{33}{3} = 11$ games.
Substitute and Verify: To check which equation fits, we substitute $g = 11$ into the choices. For choice (B) $3g + 2 = 35$ , substituting gives $3(11) + 2 = 35$ , which simplifies to $33 + 2 = 35$ , which is correct.