ame $\qquad$ ifferent Area, Same Perimeter $\newline$ $1$ through $3$ , use grid paper to draw two different rectangles with given perimeter. Tell the dimensions and area of each rectangle. cle the one that has the greater area. $\newline$ $12$ meters $\newline$ $2$ . $28$ inches $\newline$ $3$ . $20$ feet

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Q. ame

\qquad

ifferent Area, Same Perimeter

\newline

1

through

3

, use grid paper to draw two different rectangles with given perimeter. Tell the dimensions and area of each rectangle. cle the one that has the greater area.

\newline

12

meters

\newline

2

28

inches

\newline

3

20

feet

Square Area Calculation: For a perimeter of $12$ meters, let's choose dimensions for the first rectangle. If we use $3$ meters for one side, the other side will be $(12 - 2\times3) / 2 = 3$ meters. So, it's a square.
Second Rectangle Area: Now, calculate the area of this square. Area = $\text{side} \times \text{side} = 3 \, \text{meters} \times 3 \, \text{meters} = 9 \, \text{square meters}$ .
Rectangle Area Calculation: For the second rectangle with a perimeter of $12$ meters, let's choose different dimensions. If one side is $4$ meters, the other side will be $(12 - 2\times4) / 2 = 2$ meters.
Second Rectangle Area: Calculate the area of this second rectangle. Area = $\text{length} \times \text{width} = 4 \, \text{meters} \times 2 \, \text{meters} = 8 \, \text{square meters}.$
Rectangle Area Calculation: Now, for a perimeter of $28$ inches, let's choose dimensions for the first rectangle. If one side is $10$ inches, the other side will be $(28 - 2 \times 10) / 2 = 4$ inches.
Second Rectangle Area: Calculate the area of this rectangle. Area = $\text{length} \times \text{width} = 10 \, \text{inches} \times 4 \, \text{inches} = 40 \, \text{square inches}.$
Second Rectangle Area: Calculate the area of this rectangle. Area = $\text{length} \times \text{width} = 10 \, \text{inches} \times 4 \, \text{inches} = 40 \, \text{square inches}$ .For the second rectangle with a perimeter of $28 \, \text{inches}$ , let's choose different dimensions. If one side is $11 \, \text{inches}$ , the other side will be $(28 - 2 \times 11) / 2 = 3 \, \text{inches}$ .
Second Rectangle Area: Calculate the area of this rectangle. Area = length $\times$ width = $10$ inches $\times$ $4$ inches = $40$ square inches.For the second rectangle with a perimeter of $28$ inches, let's choose different dimensions. If one side is $11$ inches, the other side will be $(28 - 2\times11) / 2 = 3$ inches.Calculate the area of this second rectangle. Area = length $\times$ width = $11$ inches $\times$ $10$ $1$ inches = $10$ $2$ square inches.
Second Rectangle Area: Calculate the area of this rectangle. Area = length $\times$ width = $10$ inches $\times$ $4$ inches = $40$ square inches.For the second rectangle with a perimeter of $28$ inches, let's choose different dimensions. If one side is $11$ inches, the other side will be $(28 - 2\times11) / 2 = 3$ inches.Calculate the area of this second rectangle. Area = length $\times$ width = $11$ inches $\times$ $10$ $1$ inches = $10$ $2$ square inches.For a perimeter of $10$ $3$ feet, let's choose dimensions for the first rectangle. If one side is $10$ $4$ feet, the other side will be $10$ $5$ feet.
Second Rectangle Area: Calculate the area of this rectangle. Area = length $\times$ width = $10$ inches $\times$ $4$ inches = $40$ square inches.For the second rectangle with a perimeter of $28$ inches, let's choose different dimensions. If one side is $11$ inches, the other side will be $(28 - 2\times11) / 2 = 3$ inches.Calculate the area of this second rectangle. Area = length $\times$ width = $11$ inches $\times$ $10$ $1$ inches = $10$ $2$ square inches.For a perimeter of $10$ $3$ feet, let's choose dimensions for the first rectangle. If one side is $10$ $4$ feet, the other side will be $10$ $5$ feet.Calculate the area of this rectangle. Area = length $\times$ width = $10$ $4$ feet $\times$ $4$ feet = $\times$ $0$ square feet.
Second Rectangle Area: Calculate the area of this rectangle. Area = length $\times$ width = $10$ inches $\times$ $4$ inches = $40$ square inches.For the second rectangle with a perimeter of $28$ inches, let's choose different dimensions. If one side is $11$ inches, the other side will be $(28 - 2\times11) / 2 = 3$ inches.Calculate the area of this second rectangle. Area = length $\times$ width = $11$ inches $\times$ $10$ $1$ inches = $10$ $2$ square inches.For a perimeter of $10$ $3$ feet, let's choose dimensions for the first rectangle. If one side is $10$ $4$ feet, the other side will be $10$ $5$ feet.Calculate the area of this rectangle. Area = length $\times$ width = $10$ $4$ feet $\times$ $4$ feet = $\times$ $0$ square feet.For the second rectangle with a perimeter of $10$ $3$ feet, let's choose different dimensions. If one side is $\times$ $2$ feet, the other side will be $\times$ $3$ feet.
Second Rectangle Area: Calculate the area of this rectangle. Area = length $\times$ width = $10$ inches $\times$ $4$ inches = $40$ square inches.For the second rectangle with a perimeter of $28$ inches, let's choose different dimensions. If one side is $11$ inches, the other side will be $(28 - 2\times11) / 2 = 3$ inches.Calculate the area of this second rectangle. Area = length $\times$ width = $11$ inches $\times$ $10$ $1$ inches = $10$ $2$ square inches.For a perimeter of $10$ $3$ feet, let's choose dimensions for the first rectangle. If one side is $10$ $4$ feet, the other side will be $10$ $5$ feet.Calculate the area of this rectangle. Area = length $\times$ width = $10$ $4$ feet $\times$ $4$ feet = $\times$ $0$ square feet.For the second rectangle with a perimeter of $10$ $3$ feet, let's choose different dimensions. If one side is $\times$ $2$ feet, the other side will be $\times$ $3$ feet.Calculate the area of this second rectangle. Area = length $\times$ width = $\times$ $2$ feet $\times$ $10$ $1$ feet = $\times$ $8$ square feet.