Allison spends a winter day recording the temperature once every three hours for science class. At $9 \mathrm{am}$ , the temperature was $-13^{\circ} \mathrm{F}$ . Between $9 \mathrm{am}$ and noon, the temperature increased by $14 \cdot 1^{\circ} \mathrm{F}$ . Between noon and $3 \mathrm{pm}$ , the temperature went down $1.1^{\circ} \mathrm{F}$ . Between $3 \mathrm{pm}$ and $6 \mathrm{pm}$ , the temperature went down $9.1^{\circ} \mathrm{F}$ . What was the temperature at $6 \mathrm{pm}$ ? $\newline$ Answer: $\square$ $^{\circ} \mathrm{F}$

Full solution

Q. Allison spends a winter day recording the temperature once every three hours for science class. At

9 \mathrm{am}

, the temperature was

-13^{\circ} \mathrm{F}

. Between

9 \mathrm{am}

and noon, the temperature increased by

14 \cdot 1^{\circ} \mathrm{F}

. Between noon and

3 \mathrm{pm}

, the temperature went down

1.1^{\circ} \mathrm{F}

. Between

3 \mathrm{pm}

and

6 \mathrm{pm}

, the temperature went down

9.1^{\circ} \mathrm{F}

. What was the temperature at

6 \mathrm{pm}

\newline

Answer:

\square

^{\circ} \mathrm{F}

Initial Temperature Determination: Determine the initial temperature at $9\text{am}$ . The initial temperature at $9\text{am}$ is given as $-13\degree\text{F}$ .
Noon Temperature Calculation: Calculate the temperature at noon after the increase. $\newline$ The temperature increased by $14\degree\text{F}$ between $9$ am and noon. So, we add $14\degree\text{F}$ to the initial temperature of $-13\degree\text{F}$ . $\newline$ Calculation: $-13\degree\text{F} + 14\degree\text{F} = 1\degree\text{F}$ .
$3$ pm Temperature Calculation: Calculate the temperature at $3$ pm after the decrease. $\newline$ The temperature decreased by $1.1\degree F$ between noon and $3$ pm. So, we subtract $1.1\degree F$ from the temperature at noon. $\newline$ Calculation: $1\degree F - 1.1\degree F = -0.1\degree F$ .
$6$ pm Temperature Calculation: Calculate the temperature at $6$ pm after the second decrease. $\newline$ The temperature decreased by $9.1\degree F$ between $3$ pm and $6$ pm. So, we subtract $9.1\degree F$ from the temperature at $3$ pm. $\newline$ Calculation: $-0.1\degree F - 9.1\degree F = -9.2\degree F$ .