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Algebra Review $\newline$ Question $26$ of $35$ $(1$ point) I Cuestion Attempt: $1$ of $1$ $\newline$ $14$ $\newline$ $=15\quad=16\quad=17\quad=18\quad=19$ $\newline$ Translate the sentence into an equation. $\newline$ Twice the difference of a number and $5$ is $7$ . $\newline$ Use the variable $\newline$ $y$ for the unknown number.

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Full solution

Q. Algebra Review

\newline

Question

26

of

35

(1

point) I Cuestion Attempt:

1

of

1

\newline

14

\newline

=15\quad=16\quad=17\quad=18\quad=19

\newline

Translate the sentence into an equation.

\newline

Twice the difference of a number and

5

is

7

.

\newline

Use the variable

\newline

y

for the unknown number.

Identify Components: Identify the components of the statement to form an equation. $\newline$ ＂Twice the difference of a number and $5$ ＂ can be written as $2(y - 5)$ . $\newline$ The statement says this is equal to $7$ , so the equation is $2(y - 5) = 7$ .
Distribute $2$ : Distribute the $2$ into the parentheses. $\newline$ Multiply $2$ by each term inside the parentheses: $2 \times y$ and $2 \times (-5)$ . $\newline$ This gives us $2y - 10 = 7$ .
Add $10$ : Add $10$ to both sides of the equation to isolate the term with the variable $y$ . $\newline$ $2y - 10 + 10 = 7 + 10$ , which simplifies to $2y = 17$ .
Divide by $2$ : Divide both sides of the equation by $2$ to solve for $y$ . $\frac{2y}{2} = \frac{17}{2}$ , which simplifies to $y = \frac{17}{2}$ or $y = 8.5$ .

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