Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Algebra Review Question 19 of 35 (1 point) | Question Attempt: 1 of 1 14 15 16 17 =18 =19 =2 Simplify. (2)/(3)c-(1)/(5)c

Algebra Review\newlineQuestion 1919 of 3535 (11 point) | Question Attempt: 11 of 11\newline1414\newline1515\newline1616\newline1717\newline=18 =18 \newline=19 =19 \newline=2 =2 \newlineSimplify.\newline23c−15c \frac{2}{3} c-\frac{1}{5} c

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 2right chevron icon
Solve a system of equations using eliminationright chevron icon

Full solution

Q. Algebra Review\newlineQuestion 1919 of 3535 (11 point) | Question Attempt: 11 of 11\newline1414\newline1515\newline1616\newline1717\newline=18 =18 \newline=19 =19 \newline=2 =2 \newlineSimplify.\newline23c−15c \frac{2}{3} c-\frac{1}{5} c
  1. Identify Variable: Identify the common variable in both terms. In this case, the variable is cc.
  2. Find Common Denominator: Find a common denominator for the fractions to combine them. The denominators are 33 and 55, so the common denominator is 3×5=153 \times 5 = 15.
  3. Convert to Common Denominator: Convert each fraction to have the common denominator of 1515. This means multiplying the numerator and denominator of each fraction by the necessary factor to make the denominator 1515. For the first fraction, 23c\frac{2}{3}c, multiply by 55\frac{5}{5} to get 1015c\frac{10}{15}c. For the second fraction, 15c\frac{1}{5}c, multiply by 33\frac{3}{3} to get 315c\frac{3}{15}c.
  4. Rewrite with New Fractions: Rewrite the expression with the new fractions. The expression now is (1015)c−(315)c(\frac{10}{15})c - (\frac{3}{15})c.
  5. Subtract Numerators: Subtract the numerators of the fractions and keep the common denominator. This gives us (10−3)/15×c(10 - 3)/15 \times c, which simplifies to (7/15)c(7/15)c.
  6. Write Final Expression: Write the final simplified expression. The simplified expression is (715)c(\frac{7}{15})c.

More problems from Solve a system of equations using elimination

Question
Solve using substitution. 5x−2y=−7 5x - 2y = -7 x=−5 x = -5 (_,_)
Get tutor helpright-arrow

Posted 2 months ago

Question
Is (1,1)(1,1) a solution to this system of equations? \newline4x+10y=144x + 10y = 14\newlinex+6y=7x + 6y = 7\newlineChoices:\newline(A) yes \newline(B) no
Get tutor helpright-arrow

Posted 2 months ago

Question
Which describes the system of equations below?\newliney=–3x+9y = –3x + 9 \newliney=–3x+9y = –3x + 9 \newlineChoices:\newline(A) consistent and independent\text{(A) consistent and independent} \newline(B) consistent and dependent\text{(B) consistent and dependent} \newline(C) inconsistent\text{(C) inconsistent}
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve using elimination. \newline7x−8y=−17 7x - 8y = -17 \newline −7x+3y=2 -7x + 3y = 2 \newline (____,____)(\_\_\_\_, \_\_\_\_)
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve. \newlinex=−2 x = -2 \newline−2x+2y=−8 -2x + 2y = -8 \newline(____,____)(\_\_\_\_, \_\_\_\_)
Get tutor helpright-arrow

Posted 2 months ago

Question
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.\newlineAt a community barbecue, Mrs. Wilkerson and Mr. Hogan are buying dinner for their families. Mrs. Wilkerson purchases 33 hot dog meals and 33 hamburger meals, paying a total of $36\$36. Mr. Hogan buys 11 hot dog meal and 33 hamburger meals, spending $26\$26 in all. How much do the meals cost?\newlineHot dog meals cost $\$_______ each, and hamburger meals cost $\$________ each.
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve the system of equations by substitution.\newline−3x−y−3z=−11-3x - y - 3z = -11\newlinez=5z = 5\newlinex−y+3z=19x - y + 3z = 19\newline(____.____,____)
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve the system of equations by elimination.\newlinex−3y−2z=10 x - 3y - 2z = 10 \newline3x+2y+2z=14 3x + 2y + 2z = 14 \newline2x−3y−2z=16 2x - 3y - 2z = 16 \newline(_,_,_)(\_,\_,\_)
Get tutor helpright-arrow

Posted 1 month ago

Question
Solve the system of equations.\newliney=x2+36x+3 y = x^2 + 36x + 3 \newliney=22x−37 y = 22x - 37 \newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(_,_)(\_,\_)\newline(_,_)(\_,\_)
Get tutor helpright-arrow

Posted 1 month ago

Question
Solve the system of equations.\newliney=−x−24 y = -x - 24 \newlinex2+y2=488 x^2 + y^2 = 488 \newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(_,_) (\_,\_) \newline(_,_) (\_,\_)
Get tutor helpright-arrow

Posted 2 months ago

View all (129)