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Algebra Review $\newline$ Question $19$ of $35$ ( $1$ point) | Question Attempt: $1$ of $1$ $\newline$ $14=15=16\quad=17=18\quad=19$ $\newline$ $=2$ $\newline$ Simplify. $\newline$ $\frac{2}{3}c-\frac{1}{5}c$

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Choose two-step equations: word problems

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Q. Algebra Review

\newline

Question

19

of

35

(

1

point) | Question Attempt:

1

of

1

\newline

14=15=16\quad=17=18\quad=19

\newline

=2

\newline

Simplify.

\newline

\frac{2}{3}c-\frac{1}{5}c

Identify Variable: Identify the common variable in both terms. Both terms have the variable $c$ . We will combine like terms by subtracting the coefficients.
Find Common Denominator: Find a common denominator for the fractions $(\frac{2}{3})$ and $(\frac{1}{5})$ . $\newline$ The common denominator for $3$ and $5$ is $15$ .
Convert to Common Denominator: Convert each fraction to an equivalent fraction with the common denominator. $\newline$ $(\frac{2}{3})c$ becomes $(\frac{2\times5}{3\times5})c$ which is $(\frac{10}{15})c$ . $\newline$ $(\frac{1}{5})c$ becomes $(\frac{1\times3}{5\times3})c$ which is $(\frac{3}{15})c$ .
Subtract Fractions: Subtract the new fractions. $\newline$ $(\frac{10}{15})c - (\frac{3}{15})c = \frac{10-3}{15} c = \frac{7}{15}c$ .
Write Final Expression: Write the final simplified expression. $\newline$ The simplified expression is $(\frac{7}{15})c$ .

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