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ALEKS rww-awu.aleks.com/alekscgi/x/lsl.exe/10_u-lgNsIkr7j8f Algebraic Equations and Inequalities Solving a word problem using a quadratic A ball is thrown from a height of 40 meter h=40-5t-5t^(2) How long after the ball is thrown does it Round your answer(s) to the nearest hun (If there is more than one answer, use th

ALEKS\newlinerww-awu.aleks.com/alekscgi/x/lsl.exe/1010_u-lgNsIkr77j88f\newlineAlgebraic Equations and Inequalities\newlineSolving a word problem using a quadratic\newlineA ball is thrown from a height of 4040 meter\newlineh=40−5t−5t2 h=40-5 t-5 t^{2} \newlineHow long after the ball is thrown does it\newlineRound your answer(s) to the nearest hun (If there is more than one answer, use th

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Q. ALEKS\newlinerww-awu.aleks.com/alekscgi/x/lsl.exe/1010_u-lgNsIkr77j88f\newlineAlgebraic Equations and Inequalities\newlineSolving a word problem using a quadratic\newlineA ball is thrown from a height of 4040 meter\newlineh=40−5t−5t2 h=40-5 t-5 t^{2} \newlineHow long after the ball is thrown does it\newlineRound your answer(s) to the nearest hun (If there is more than one answer, use th
  1. Rewrite equation in standard form: Rewrite the equation h=40−5t−5t2h=40-5t-5t^2 as a quadratic equation in standard form: 0=−5t2−5t+400 = -5t^2 - 5t + 40.
  2. Divide by −5-5: Divide the entire equation by −5-5 to simplify: 0=t2+t−80 = t^2 + t - 8.
  3. Factor the quadratic equation: Factor the quadratic equation: 0=(t+4)(t−2)0 = (t + 4)(t - 2).
  4. Set equal and solve for tt: Set each factor equal to zero and solve for tt: t+4=0t + 4 = 0 or t−2=0t - 2 = 0.
  5. Find physical solution: Solve for tt: t=−4t = -4 or t=2t = 2.
  6. Find physical solution: Solve for tt: t=−4t = -4 or t=2t = 2.Since time cannot be negative, discard t=−4t = -4 and keep t=2t = 2 as the physical solution.

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