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Ai Mi deposits 
$910 every month into an account earning an annual interest rate of 
3.9% compounded monthly. How much would she have in the account after 13 years, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Ai Mi deposits $910 \$ 910 every month into an account earning an annual interest rate of 3.9% 3.9 \% compounded monthly. How much would she have in the account after 1313 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Ai Mi deposits $910 \$ 910 every month into an account earning an annual interest rate of 3.9% 3.9 \% compounded monthly. How much would she have in the account after 1313 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Variables: First, let's identify the variables needed to use the formula A=d((1+i)n1)/iA=d\left(\left(1+i\right)^{n}-1\right)/i:d=$910d = \$910 (monthly deposit)i=3.9%i = 3.9\% annual interest rate compounded monthly, which needs to be converted to a monthly rate by dividing by 1212n=13n = 13 years, but since the compounding is monthly, we need to multiply by 1212 to get the number of periods
  2. Calculate Monthly Interest Rate: Now, let's calculate the monthly interest rate ( extit{i}):
    extit{i} = annual interest rate / 1212
    extit{i} = 3.9%/123.9\% / 12
    extit{i} = 0.039/120.039 / 12
    extit{i} = 0.003250.00325
  3. Calculate Number of Periods: Next, we calculate the number of periods nn:n=years×12n = \text{years} \times 12 (since the deposits are monthly)n=13×12n = 13 \times 12n=156n = 156
  4. Calculate Future Value: Now we can use the formula to calculate the future value of the account AA:
    A=d×((1+i)n1)/iA = d \times \left(\left(1 + i\right)^{n} - 1\right) / i
    A=910×((1+0.00325)1561)/0.00325A = 910 \times \left(\left(1 + 0.00325\right)^{156} - 1\right) / 0.00325
  5. Calculate Inside Parentheses: Let's calculate the part inside the parentheses first:\newline(1+i)n1(1 + i)^{n} - 1\newline(1+0.00325)1561(1 + 0.00325)^{156} - 1
  6. Calculate Exponential Value: Now, we calculate (1+0.00325)156(1 + 0.00325)^{156}:\newline(1+0.00325)1561.647(1 + 0.00325)^{156} \approx 1.647
  7. Subtract One: Subtract 11 from the result:\newline1.64710.6471.647 - 1 \approx 0.647
  8. Divide by i: Now we divide this result by i: 0.647/0.00325199.07690.647 / 0.00325 \approx 199.0769
  9. Multiply by dd: Finally, we multiply this result by dd to get AA:A=910×199.0769A = 910 \times 199.0769A181155.979A \approx 181155.979
  10. Round Final Amount: Since we need to round to the nearest dollar, the final amount in the account will be: A$(181,156)A \approx \$(181,156)

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