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After touring a coffee bean farm, Lily impulsively bought 88 bags of coffee beans. Of the bags she bought, 66 were filled with caramel flavored coffee beans.\newlineIf Lily randomly selects 55 of the bags to send to family members, what is the probability that all of them are caramel flavored?\newlineWrite your answer as a decimal rounded to four decimal places.\newline____\newline

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Q. After touring a coffee bean farm, Lily impulsively bought 88 bags of coffee beans. Of the bags she bought, 66 were filled with caramel flavored coffee beans.\newlineIf Lily randomly selects 55 of the bags to send to family members, what is the probability that all of them are caramel flavored?\newlineWrite your answer as a decimal rounded to four decimal places.\newline____\newline
  1. Calculate Total Ways: Total number of bags: 88\newlineBags to choose for sending: 55\newlineCalculate the total number of ways to choose 55 bags out of 88.\newlineTotal outcomes: 8C5_8C_5
  2. Calculate Value: Find the value of 8C5 {}_8C_5 .8C5=8!5!(85)!=8!5!3!=8×7×6×5!5!×3×2×1=56 {}_8C_5 = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6 \times 5!}{5! \times 3 \times 2 \times 1} = 56
  3. Choose Caramel Bags: Number of caramel flavored bags: 66 Number of chosen caramel flavored bags: 55 Calculate the number of ways to choose 55 caramel flavored bags out of 66. Favorable outcomes: 6C5_{6}C_{5}
  4. Calculate Value: Find the value of (65)\binom{6}{5}.\newline(65)=6!5!(65)!\binom{6}{5} = \frac{6!}{5!(6-5)!}\newline=6!5!1!= \frac{6!}{5!1!}\newline=6×5!5!×1= \frac{6 \times 5!}{5! \times 1}\newline=6= 6
  5. Calculate Probability: Calculate the probability that all selected bags are caramel flavored.\newlineProbability = Favorable outcomes / Total possible outcomes\newline= 656\frac{6}{56}\newline0.1071\approx 0.1071

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