ade > BB. $11$ Area of compound figures made of rectangles NBA $\newline$ What is the area of this figure? $\newline$ $\square$ square meters $\newline$ Submit $\newline$ Work $\newline$ Search

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Area of quadrilaterals and triangles: word problems

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Q. ade > BB.

11

Area of compound figures made of rectangles NBA

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What is the area of this figure?

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square meters

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Submit

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Work

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Breakdown of Compound Figure: First, we need to break down the compound figure into individual rectangles, so we can calculate the area of each one separately.
Calculate Area of Rectangle $A$ : Let's say the compound figure is made up of $2$ rectangles, Rectangle $A$ and Rectangle $B$ . We need to find the length and width of each rectangle.
Calculate Area of Rectangle B: Assuming Rectangle A has a length of $10$ meters and a width of $5$ meters, the area of Rectangle A is length times width, so $10$ m $*$ $5$ m.
Find Total Area: Calculating the area of Rectangle A: $10\,\text{m} \times 5\,\text{m} = 50\,\text{square meters}.$
Find Total Area: Calculating the area of Rectangle A: $10\,\text{m} \times 5\,\text{m} = 50\,\text{square meters}$ .Now, let's find the area of Rectangle B. If Rectangle B has a length of $8\,\text{meters}$ and a width of $3\,\text{meters}$ , then its area is also length times width, so $8\,\text{m} \times 3\,\text{m}$ .
Find Total Area: Calculating the area of Rectangle A: $10\,\text{m} \times 5\,\text{m} = 50\,\text{square meters}$ .Now, let's find the area of Rectangle B. If Rectangle B has a length of $8\,\text{meters}$ and a width of $3\,\text{meters}$ , then its area is also length times width, so $8\,\text{m} \times 3\,\text{m}$ .Calculating the area of Rectangle B: $8\,\text{m} \times 3\,\text{m} = 24\,\text{square meters}$ .
Find Total Area: Calculating the area of Rectangle A: $10\,\text{m} \times 5\,\text{m} = 50$ square meters.Now, let's find the area of Rectangle B. If Rectangle B has a length of $8$ meters and a width of $3$ meters, then its area is also length times width, so $8\,\text{m} \times 3\,\text{m}$ .Calculating the area of Rectangle B: $8\,\text{m} \times 3\,\text{m} = 24$ square meters.To find the total area of the compound figure, we add the areas of Rectangle A and Rectangle B together.
Find Total Area: Calculating the area of Rectangle A: $10\,\text{m} \times 5\,\text{m} = 50\,\text{square meters}$ .Now, let's find the area of Rectangle B. If Rectangle B has a length of $8\,\text{meters}$ and a width of $3\,\text{meters}$ , then its area is also length times width, so $8\,\text{m} \times 3\,\text{m}$ .Calculating the area of Rectangle B: $8\,\text{m} \times 3\,\text{m} = 24\,\text{square meters}$ .To find the total area of the compound figure, we add the areas of Rectangle A and Rectangle B together.Adding the areas: $50\,\text{square meters} + 24\,\text{square meters} = 74\,\text{square meters}$ .