Addison is a physical therapist who specializes in pediatric leg injuries. Her patients differ in age and type of injury.\begin{tabular}{|l|c|c|}\hline & Knee pain & Ankle pain \\\hline 0−12 years old & 3 & 6 \\\hline 13−19 years old & 4 & 5 \\\hline\end{tabular}What is the probability that a randomly selected patient is not 13−19 years old and does not suffer from ankle pain?Simplify any fractions.□
Q. Addison is a physical therapist who specializes in pediatric leg injuries. Her patients differ in age and type of injury.\begin{tabular}{|l|c|c|}\hline & Knee pain & Ankle pain \\\hline 0−12 years old & 3 & 6 \\\hline 13−19 years old & 4 & 5 \\\hline\end{tabular}What is the probability that a randomly selected patient is not 13−19 years old and does not suffer from ankle pain?Simplify any fractions.□
Find Total Patients: First, let's find the total number of patients. Add up all the patients in the table.Total patients = 3(0−12,extKnee)+6(0−12,extAnkle)+4(13−19, ext{Knee}) + 5 $(\(13\)\(-19\), ext{Ankle})\(\newline\)Total patients = \(3 + 6 + 4 + 5\)\(\newline\)Total patients = \(18\)
Find Patients Not \(13\)\(-19\): Now, let's find the number of patients who are not \(13\)-\(19\) years old and do not have ankle pain.\(\newline\)This is the number of patients who are \(0\)-\(12\) years old with knee pain.\(\newline\)Patients not \(13\)-\(19\) years old and without ankle pain = \(3\) (\(0\)-\(12\), Knee)
Calculate Probability: Calculate the probability.\(\newline\)Probability = Number of patients not \(13\)-\(19\) years old and without ankle pain / Total number of patients\(\newline\)Probability = \(\frac{3}{18}\)
Simplify Fraction: Simplify the fraction.\(\newline\)Probability = \(\frac{1}{6}\)
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