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Addison has the following data:\newline11,c,4,9,7,1211, c, 4, 9, 7, 12\newlineIf the mean is 99, which number could cc be?\newlineChoices:\newline(A)(A) 55\newline(B)(B) 1111

Full solution

Q. Addison has the following data:\newline11,c,4,9,7,1211, c, 4, 9, 7, 12\newlineIf the mean is 99, which number could cc be?\newlineChoices:\newline(A)(A) 55\newline(B)(B) 1111
  1. Calculate total number of terms: Calculate the total number of terms in the data set.\newlineData set: 11,c,4,9,7,1211, c, 4, 9, 7, 12\newlineNumber of terms: 66
  2. Set up mean equation: Set up the equation using the mean formula.\newlineMean formula: Mean = sum of all termsnumber of terms\frac{\text{sum of all terms}}{\text{number of terms}}\newlineGiven mean = 99\newline9=11+c+4+9+7+1269 = \frac{11 + c + 4 + 9 + 7 + 12}{6}
  3. Simplify sum in equation: Simplify the sum inside the equation.\newlineSum of known terms = 11+4+9+7+12=4311 + 4 + 9 + 7 + 12 = 43\newline9=(43+c)/69 = (43 + c) / 6
  4. Solve for c: Solve for c.\newlineMultiply both sides by 66 to clear the fraction:\newline9×6=(43+c)9 \times 6 = (43 + c)\newline54=43+c54 = 43 + c
  5. Isolate c: Isolate c.\newline5443=c54 - 43 = c\newlinec=11c = 11

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