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Adam deposits 
$200 every month into an account earning a monthly interest rate of 
0.675%. How much would he have in the account after 2 years, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Adam deposits $200 \$ 200 every month into an account earning a monthly interest rate of 0.675% 0.675 \% . How much would he have in the account after 22 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Adam deposits $200 \$ 200 every month into an account earning a monthly interest rate of 0.675% 0.675 \% . How much would he have in the account after 22 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify variables: Identify the variables from the problem.\newlineWe are given:\newlined=$200d = \$200 (the amount invested at the end of each period)\newlinei=0.675%i = 0.675\% per month (the interest rate per period)\newlinen=2n = 2 years 12* 12 months/year =24= 24 periods (the number of periods)\newlineNow, convert the interest rate from a percentage to a decimal for the calculation.\newlinei=0.675%=0.675100=0.00675i = 0.675\% = \frac{0.675}{100} = 0.00675
  2. Use formula: Use the formula to calculate the future value of the account.\newlineA=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)\newlineSubstitute the values into the formula.\newlineA=200×((1+0.00675)2410.00675)A = 200 \times \left(\frac{(1 + 0.00675)^{24} - 1}{0.00675}\right)
  3. Calculate values: Calculate the value inside the parentheses and the exponent.\newlineCalculate (1+i)n(1 + i)^{n}:\newline(1+0.00675)241.0067524(1 + 0.00675)^{24} \approx 1.00675^{24}\newlineUse a calculator to find the value.\newline1.00675241.1716031.00675^{24} \approx 1.171603
  4. Continue calculation: Continue with the formula calculation.\newlineNow, subtract 11 from the result obtained in the previous step.\newline1.17160310.1716031.171603 - 1 \approx 0.171603
  5. Complete formula: Complete the formula calculation.\newlineDivide the result by ii and multiply by dd.\newlineA=200×(0.171603/0.00675)A = 200 \times (0.171603 / 0.00675)\newlineUse a calculator to find the value.\newlineA200×25.422222A \approx 200 \times 25.422222
  6. Multiply amount: Multiply by the amount invested at the end of each period.\newlineA200×25.422222A \approx 200 \times 25.422222\newlineA5084.4444A \approx 5084.4444
  7. Round final answer: Round the final answer to the nearest dollar.\newlineA$5084A \approx \$5084

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