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According to Descartes' Rule of Signs, can the polynomial function have exactly 11 positive real zero, including any repeated zeros? Choose your answer based on the rule only.\newlineg(x)=x4+5x39x2+9x+8g(x) = x^4 + 5x^3 - 9x^2 + 9x + 8\newlineChoices:\newline(A)yes\newline(B)no

Full solution

Q. According to Descartes' Rule of Signs, can the polynomial function have exactly 11 positive real zero, including any repeated zeros? Choose your answer based on the rule only.\newlineg(x)=x4+5x39x2+9x+8g(x) = x^4 + 5x^3 - 9x^2 + 9x + 8\newlineChoices:\newline(A)yes\newline(B)no
  1. Count Sign Changes: Count the number of sign changes in the coefficients of g(x)=x4+5x39x2+9x+8g(x) = x^4 + 5x^3 - 9x^2 + 9x + 8. Coefficients: 1,5,9,9,81, 5, -9, 9, 8. Sign changes: 11 (from 55 to 9-9).
  2. Descartes' Rule of Signs: According to Descartes' Rule of Signs, the number of positive real zeros is equal to the number of sign changes or less by an even number.\newlineSince we have 11 sign change, g(x)g(x) can have 11 or 00 positive real zeros.
  3. Check Positive Real Zeros: Check if g(x)g(x) can have exactly 11 positive real zero.\newlineSince the possible number of positive real zeros is 11 or 00, it can have exactly 11 positive real zero.

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