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ABC is a right-angled triangle.
Calculate the length of 
BC.
Give your answer correct to 1 decimal place.

ABC A B C is a right-angled triangle.\newlineCalculate the length of BC B C .\newlineGive your answer correct to 11 decimal place.

Full solution

Q. ABC A B C is a right-angled triangle.\newlineCalculate the length of BC B C .\newlineGive your answer correct to 11 decimal place.
  1. Pythagoras' Theorem: We need to use Pythagoras' theorem, which is a2+b2=c2a^2 + b^2 = c^2, where cc is the hypotenuse and aa and bb are the other two sides.
  2. Plug in Values: Let's say we know the lengths of sides ABAB and ACAC. We can plug these values into the theorem to find BCBC.
  3. Calculate BC: Suppose AB=4cmAB = 4\,\text{cm} and AC=3cmAC = 3\,\text{cm}. Then we calculate BCBC as follows: BC2=AB2+AC2BC^2 = AB^2 + AC^2.
  4. Square Root: So, BC2=42+32=16+9=25BC^2 = 4^2 + 3^2 = 16 + 9 = 25.
  5. Correcting Mistake: Now, we take the square root of both sides to find BC: BC=25.BC = \sqrt{25}.
  6. Correcting Mistake: Now, we take the square root of both sides to find BCBC: BC=25BC = \sqrt{25}. Calculating the square root, we get BC=5.0cmBC = 5.0\,\text{cm}.
  7. Correcting Mistake: Now, we take the square root of both sides to find BC: BC=25BC = \sqrt{25}.Calculating the square root, we get BC=5.0cmBC = 5.0\,\text{cm}.But wait, we made a mistake. Pythagoras' theorem is c2=a2+b2c^2 = a^2 + b^2, not a2+b2=c2a^2 + b^2 = c^2. We need to correct this.

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