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A(x)=(88+22x)^22

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Q. A(x)=(88+22x)^22
  1. Identify Function: Identify the function that needs to be differentiated. The function is A(x)=(8+2x)2A(x) = (8+2x)^2.
  2. Find Inner Derivative: Find the derivative of the inner function, u(x)=8+2xu(x) = 8+2x. The derivative of u(x)u(x) with respect to xx is dudx=2\frac{du}{dx} = 2.
  3. Apply Chain Rule: Apply the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the derivative of A(x)=(8+2x)2A(x) = (8+2x)^2 is dAdx=2(8+2x)21dudx\frac{dA}{dx} = 2\cdot(8+2x)^{2-1}\cdot\frac{du}{dx}.
  4. Simplify Expression: Simplify the derivative expression. The derivative of A(x)=(8+2x)2A(x) = (8+2x)^2 is dAdx=2(8+2x)2\frac{dA}{dx} = 2\cdot(8+2x)\cdot2.
  5. Perform Multiplication: Perform the multiplication to get the final derivative. The derivative of A(x)=(8+2x)2A(x) = (8+2x)^2 is dAdx=4(8+2x)\frac{dA}{dx} = 4\cdot(8+2x).
  6. Expand Final Form: Expand the expression to get the final simplified form of the derivative. The derivative of A(x)=(8+2x)2A(x) = (8+2x)^2 is dAdx=48+42x=32+8x\frac{dA}{dx} = 4\cdot8 + 4\cdot2x = 32 + 8x.

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