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A={x|-3 <= x < -(1)/(2)},B={x∣-1 < x <= 3} dan C={x|(1)/(2) < x < 5} a. A uu B={x|-3 <= x < -(1)/(2)uu-1 < x <= 3}=dots. b. quad A nn B={x|-3 <= x < -(1)/(2)nn-1 < x <= 3}=dots... c. quad(A uu B)nn C=dots={x|-3 <= x <= 3nn(1)/(2) < x < 5}=dots. d. (A nn B)uu C=dots={x|-1 < x < -(1)/(2)uu(1)/(2) < x < 5}=dots. quad A={x∣x^(2)-x-2=0},B={x∣x^(2)-x-6=0}, dan C={x∣x^(2)-4=0}. A={x∣x^(2)-x-2=(x+1)(x-2)=0=>x_(1)=-1;x_(2)=2}, sehingga A={-1,2}. B={x∣x^(2)-x-6=dots.=0=>x_(1)=dots;x_(2)=dots}, sehingga B={-2,3}. C={x∣x^(2)-4=dots.=0=>dots.}, sehingga C={-2,2}. Jadi, a. A nn B={-1,2}nn{-2,3}=dots. b. (A nn B)uu C=({-1,2}nn{-2,3})uu{-2,2}=O/ uu{-2,2}=dots. c. quad(A uu B)nn C=dots. d. B-C=dots. e. C-B={-2,2}-{-2,3}=dots

33) A={x∣ −3≤x<−12},B={x∣−1<x≤3} A=\left\{x \left\lvert\,-3 \leq x<-\frac{1}{2}\right.\right\}, B=\{x \mid-1<x \leq 3\} dan C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} \newlinea. A∪B={x∣ −3≤x<−12∪−1<x≤3}=… A \cup B=\left\{x \left\lvert\,-3 \leq x<-\frac{1}{2} \cup-1<x \leq 3\right.\right\}=\ldots .\newlineb. A∩B={x∣ −3≤x<−12∩−1<x≤3}=… \quad A \cap B=\left\{x \left\lvert\,-3 \leq x<-\frac{1}{2} \cap-1<x \leq 3\right.\right\}=\ldots ...\newlinec. (A∪B)∩C=…={x∣ −3≤x≤3∩12<x<5}=… \quad(A \cup B) \cap C=\ldots=\left\{x \left\lvert\,-3 \leq x \leq 3 \cap \frac{1}{2}<x<5\right.\right\}=\ldots .\newlined. (A∩B)∪C=…={x∣ −1<x<−12∪12<x<5}=… (A \cap B) \cup C=\ldots=\left\{x \left\lvert\,-1<x<-\frac{1}{2} \cup \frac{1}{2}<x<5\right.\right\}=\ldots .\newline44) A={x∣x2−x−2=0},B={x∣x2−x−6=0} \quad A=\left\{x \mid x^{2}-x-2=0\right\}, B=\left\{x \mid x^{2}-x-6=0\right\} , dan C={x∣x2−4=0} C=\left\{x \mid x^{2}-4=0\right\} .\newlineA={x∣x2−x−2=(x+1)(x−2)=0⇒x1=−1;x2=2} A=\left\{x \mid x^{2}-x-2=(x+1)(x-2)=0 \Rightarrow x_{1}=-1 ; x_{2}=2\right\} , sehingga\newlineA={−1,2} A=\{-1,2\} .\newlineC={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 00, sehingga C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 11.\newlineC={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 22, sehingga C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 33.\newlineJadi,\newlinea. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 44.\newlineb. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 55.\newlinec. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 66.\newlined. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 77.\newlinee. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 88

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Q. 33) A={x∣ −3≤x<−12},B={x∣−1<x≤3} A=\left\{x \left\lvert\,-3 \leq x<-\frac{1}{2}\right.\right\}, B=\{x \mid-1<x \leq 3\} dan C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} \newlinea. A∪B={x∣ −3≤x<−12∪−1<x≤3}=… A \cup B=\left\{x \left\lvert\,-3 \leq x<-\frac{1}{2} \cup-1<x \leq 3\right.\right\}=\ldots .\newlineb. A∩B={x∣ −3≤x<−12∩−1<x≤3}=… \quad A \cap B=\left\{x \left\lvert\,-3 \leq x<-\frac{1}{2} \cap-1<x \leq 3\right.\right\}=\ldots ...\newlinec. (A∪B)∩C=…={x∣ −3≤x≤3∩12<x<5}=… \quad(A \cup B) \cap C=\ldots=\left\{x \left\lvert\,-3 \leq x \leq 3 \cap \frac{1}{2}<x<5\right.\right\}=\ldots .\newlined. (A∩B)∪C=…={x∣ −1<x<−12∪12<x<5}=… (A \cap B) \cup C=\ldots=\left\{x \left\lvert\,-1<x<-\frac{1}{2} \cup \frac{1}{2}<x<5\right.\right\}=\ldots .\newline44) A={x∣x2−x−2=0},B={x∣x2−x−6=0} \quad A=\left\{x \mid x^{2}-x-2=0\right\}, B=\left\{x \mid x^{2}-x-6=0\right\} , dan C={x∣x2−4=0} C=\left\{x \mid x^{2}-4=0\right\} .\newlineA={x∣x2−x−2=(x+1)(x−2)=0⇒x1=−1;x2=2} A=\left\{x \mid x^{2}-x-2=(x+1)(x-2)=0 \Rightarrow x_{1}=-1 ; x_{2}=2\right\} , sehingga\newlineA={−1,2} A=\{-1,2\} .\newlineC={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 00, sehingga C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 11.\newlineC={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 22, sehingga C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 33.\newlineJadi,\newlinea. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 44.\newlineb. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 55.\newlinec. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 66.\newlined. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 77.\newlinee. C={x∣ 12<x<5} C=\left\{x \left\lvert\, \frac{1}{2}<x<5\right.\right\} 88
  1. Combine Intervals: a. A∪B={x∣−3≤x<−12∪−1<x≤3}A \cup B = \{x | -3 \leq x < -\frac{1}{2} \cup -1 < x \leq 3\} Combine the intervals where they overlap.
  2. Find Common Interval: A∪B={x∣−3≤x≤3}A \cup B = \{x | -3 \leq x \leq 3\}
  3. Find Common Interval: b. A∩B={x∣−3≤x<−12∩−1<x≤3}A \cap B = \{x | -3 \leq x < -\frac{1}{2} \cap -1 < x \leq 3\}\newlineFind the common interval between AA and BB.
  4. Combine Intervals: A∩B={x∣−1<x<−12}A \cap B = \{x | -1 < x < -\frac{1}{2}\}
  5. Factor Quadratic Equation: c. (A∪B)∩C={x∣−3≤x≤3∩12<x<5}(A \cup B) \cap C = \{x | -3 \leq x \leq 3 \cap \frac{1}{2} < x < 5\} Find the common interval between A∪BA \cup B and CC.
  6. Factor Quadratic Equation: (A∪B)∩C={x∣12<x<3}(A \cup B) \cap C = \{x | \frac{1}{2} < x < 3\}
  7. Factor Quadratic Equation: d. (A∩B)∪C={x∣−1<x<−12∪12<x<5}(A \cap B) \cup C = \{x | -1 < x < -\frac{1}{2} \cup \frac{1}{2} < x < 5\} Combine the intervals where they do not overlap.
  8. Find Common Elements: (A∩B)∪C={x∣−1<x<5}(A \cap B) \cup C = \{x | -1 < x < 5\}
  9. Combine Sets: Solve A={x∣x2−x−2=0}A = \{x | x^2 - x - 2 = 0\}\newlineFactor the quadratic equation.
  10. Find Common Elements: A={x∣(x+1)(x−2)=0}A = \{x | (x + 1)(x - 2) = 0\} Set each factor equal to zero and solve for xx.
  11. Remove Elements: x1=−1x_1 = -1, x2=2x_2 = 2, so A={−1,2}A = \{-1, 2\}
  12. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.
  13. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx.
  14. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx.x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\}
  15. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\}Solve C={x∣x2−4=0}C = \{x | x^2 - 4 = 0\}\newlineFactor the quadratic equation.
  16. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\}Solve C={x∣x2−4=0}C = \{x | x^2 - 4 = 0\}\newlineFactor the quadratic equation.C={x∣(x+2)(x−2)=0}C = \{x | (x + 2)(x - 2) = 0\}\newlineSet each factor equal to zero and solve for xx.
  17. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\}Solve C={x∣x2−4=0}C = \{x | x^2 - 4 = 0\}\newlineFactor the quadratic equation.C={x∣(x+2)(x−2)=0}C = \{x | (x + 2)(x - 2) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}00, so B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}11
  18. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\} Solve C={x∣x2−4=0}C = \{x | x^2 - 4 = 0\}\newlineFactor the quadratic equation.C={x∣(x+2)(x−2)=0}C = \{x | (x + 2)(x - 2) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}00, so B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}11 B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}22. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}33\newlineFind the common elements between B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}44 and B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}55.
  19. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\} Solve C={x∣x2−4=0}C = \{x | x^2 - 4 = 0\}\newlineFactor the quadratic equation.C={x∣(x+2)(x−2)=0}C = \{x | (x + 2)(x - 2) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}00, so B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}11 B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}22. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}33\newlineFind the common elements between B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}44 and B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}55. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}66\newlineThere are no common elements.
  20. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\} Solve C={x∣x2−4=0}C = \{x | x^2 - 4 = 0\}\newlineFactor the quadratic equation.C={x∣(x+2)(x−2)=0}C = \{x | (x + 2)(x - 2) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}00, so B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}11 a. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}22\newlineFind the common elements between B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}33 and B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}44. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}55\newlineThere are no common elements. b. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}66\newlineCombine the sets.
  21. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\} Solve C={x∣x2−4=0}C = \{x | x^2 - 4 = 0\}\newlineFactor the quadratic equation.C={x∣(x+2)(x−2)=0}C = \{x | (x + 2)(x - 2) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}00, so B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}11 a. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}22\newlineFind the common elements between B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}33 and B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}44. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}55\newlineThere are no common elements. b. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}66\newlineCombine the sets. (A \cap B) \cup C = \{\} \cup \{\(-2\), \(2\)\}
  22. Remove Elements: Solve \(B = \{x | x^2 - x - 6 = 0\}\)\(\newline\)Factor the quadratic equation.\(B = \{x | (x + 2)(x - 3) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(x_2 = 3\), so \(B = \{-2, 3\}\)Solve \(C = \{x | x^2 - 4 = 0\}\)\(\newline\)Factor the quadratic equation.\(C = \{x | (x + 2)(x - 2) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(B = \{x | (x + 2)(x - 3) = 0\}\)\(0\), so \(B = \{x | (x + 2)(x - 3) = 0\}\)\(1\)a. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(2\)\(\newline\)Find the common elements between \(B = \{x | (x + 2)(x - 3) = 0\}\)\(3\) and \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\). \(B = \{x | (x + 2)(x - 3) = 0\}\)\(5\)\(\newline\)There are no common elements.b. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(6\)\(\newline\)Combine the sets.\(B = \{x | (x + 2)(x - 3) = 0\}\)\(7\)(A \cap B) \cup C = \{\(-2\), \(2\)\}
  23. Remove Elements: Solve \(B = \{x | x^2 - x - 6 = 0\}\)\(\newline\)Factor the quadratic equation.\(B = \{x | (x + 2)(x - 3) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(x_2 = 3\), so \(B = \{-2, 3\}\) Solve \(C = \{x | x^2 - 4 = 0\}\)\(\newline\)Factor the quadratic equation.\(C = \{x | (x + 2)(x - 2) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(B = \{x | (x + 2)(x - 3) = 0\}\)\(0\), so \(B = \{x | (x + 2)(x - 3) = 0\}\)\(1\) a. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(2\)\(\newline\)Find the common elements between \(B = \{x | (x + 2)(x - 3) = 0\}\)\(3\) and \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\). \(B = \{x | (x + 2)(x - 3) = 0\}\)\(5\)\(\newline\)There are no common elements. b. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(6\)\(\newline\)Combine the sets. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(7\) \(B = \{x | (x + 2)(x - 3) = 0\}\)\(8\) c. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(9\)\(\newline\)Find the common elements between \(x\)\(0\) and \(x\)\(1\).
  24. Remove Elements: Solve \(B = \{x | x^2 - x - 6 = 0\}\)\(\newline\)Factor the quadratic equation.\(B = \{x | (x + 2)(x - 3) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(x_2 = 3\), so \(B = \{-2, 3\}\) Solve \(C = \{x | x^2 - 4 = 0\}\)\(\newline\)Factor the quadratic equation.\(C = \{x | (x + 2)(x - 2) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(B = \{x | (x + 2)(x - 3) = 0\}\)\(0\), so \(B = \{x | (x + 2)(x - 3) = 0\}\)\(1\) a. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(2\)\(\newline\)Find the common elements between \(B = \{x | (x + 2)(x - 3) = 0\}\)\(3\) and \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\). \(B = \{x | (x + 2)(x - 3) = 0\}\)\(5\)\(\newline\)There are no common elements. b. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(6\)\(\newline\)Combine the sets. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(7\) \(B = \{x | (x + 2)(x - 3) = 0\}\)\(8\) c. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(9\)\(\newline\)Find the common elements between \(x\)\(0\) and \(x\)\(1\). (A \cup B) \cap C = \{−2-2, 22, 33\} \cap \{−2-2, 22\}
  25. Remove Elements: Solve B={x∣x2−x−6=0}B = \{x | x^2 - x - 6 = 0\}\newlineFactor the quadratic equation.B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, x2=3x_2 = 3, so B={−2,3}B = \{-2, 3\} Solve C={x∣x2−4=0}C = \{x | x^2 - 4 = 0\}\newlineFactor the quadratic equation.C={x∣(x+2)(x−2)=0}C = \{x | (x + 2)(x - 2) = 0\}\newlineSet each factor equal to zero and solve for xx. x1=−2x_1 = -2, B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}00, so B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}11 a. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}22\newlineFind the common elements between B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}33 and B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}44. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}55\newlineThere are no common elements. b. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}66\newlineCombine the sets. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}77 B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}88 c. B={x∣(x+2)(x−3)=0}B = \{x | (x + 2)(x - 3) = 0\}99\newlineFind the common elements between xx00 and xx11. xx22 (A \cup B) \cap C = \{\(-2\), \(2\)\}
  26. Remove Elements: Solve \(B = \{x | x^2 - x - 6 = 0\}\)\(\newline\)Factor the quadratic equation.\(B = \{x | (x + 2)(x - 3) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(x_2 = 3\), so \(B = \{-2, 3\}\) Solve \(C = \{x | x^2 - 4 = 0\}\)\(\newline\)Factor the quadratic equation.\(C = \{x | (x + 2)(x - 2) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(B = \{x | (x + 2)(x - 3) = 0\}\)\(0\), so \(B = \{x | (x + 2)(x - 3) = 0\}\)\(1\) a. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(2\)\(\newline\)Find the common elements between \(B = \{x | (x + 2)(x - 3) = 0\}\)\(3\) and \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\). \(B = \{x | (x + 2)(x - 3) = 0\}\)\(5\)\(\newline\)There are no common elements. b. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(6\)\(\newline\)Combine the sets. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(7\) \(B = \{x | (x + 2)(x - 3) = 0\}\)\(8\) c. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(9\)\(\newline\)Find the common elements between \(x\)\(0\) and \(x\)\(1\). \(x\)\(2\) \(x\)\(3\) d. \(x\)\(4\)\(\newline\)Remove the elements of \(x\)\(1\) from \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\).
  27. Remove Elements: Solve \(B = \{x | x^2 - x - 6 = 0\}\) Factor the quadratic equation.\(B = \{x | (x + 2)(x - 3) = 0\}\) Set each factor equal to zero and solve for \(x\).\(x_1 = -2\), \(x_2 = 3\), so \(B = \{-2, 3\}\) Solve \(C = \{x | x^2 - 4 = 0\}\) Factor the quadratic equation.\(C = \{x | (x + 2)(x - 2) = 0\}\) Set each factor equal to zero and solve for \(x\).\(x_1 = -2\), \(B = \{x | (x + 2)(x - 3) = 0\}\)\(0\), so \(B = \{x | (x + 2)(x - 3) = 0\}\)\(1\) a. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(2\) Find the common elements between \(B = \{x | (x + 2)(x - 3) = 0\}\)\(3\) and \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\).\(B = \{x | (x + 2)(x - 3) = 0\}\)\(5\) There are no common elements. b. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(6\) Combine the sets.\(B = \{x | (x + 2)(x - 3) = 0\}\)\(7\)\(B = \{x | (x + 2)(x - 3) = 0\}\)\(8\) c. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(9\) Find the common elements between \(x\)\(0\) and \(x\)\(1\).\(x\)\(2\)\(x\)\(3\) d. \(x\)\(4\) Remove the elements of \(x\)\(1\) from \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\).\(x\)\(7\)
  28. Remove Elements: Solve \(B = \{x | x^2 - x - 6 = 0\}\)\(\newline\)Factor the quadratic equation.\(B = \{x | (x + 2)(x - 3) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(x_2 = 3\), so \(B = \{-2, 3\}\) Solve \(C = \{x | x^2 - 4 = 0\}\)\(\newline\)Factor the quadratic equation.\(C = \{x | (x + 2)(x - 2) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(B = \{x | (x + 2)(x - 3) = 0\}\)\(0\), so \(B = \{x | (x + 2)(x - 3) = 0\}\)\(1\) a. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(2\)\(\newline\)Find the common elements between \(B = \{x | (x + 2)(x - 3) = 0\}\)\(3\) and \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\). \(B = \{x | (x + 2)(x - 3) = 0\}\)\(5\)\(\newline\)There are no common elements. b. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(6\)\(\newline\)Combine the sets. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(7\) \(B = \{x | (x + 2)(x - 3) = 0\}\)\(8\) c. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(9\)\(\newline\)Find the common elements between \(x\)\(0\) and \(x\)\(1\). \(x\)\(2\) \(x\)\(3\) d. \(x\)\(4\)\(\newline\)Remove the elements of \(x\)\(1\) from \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\). \(x\)\(7\) e. \(x\)\(8\)\(\newline\)Remove the elements of \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\) from \(x\)\(1\).
  29. Remove Elements: Solve \(B = \{x | x^2 - x - 6 = 0\}\)\(\newline\)Factor the quadratic equation.\(B = \{x | (x + 2)(x - 3) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(x_2 = 3\), so \(B = \{-2, 3\}\) Solve \(C = \{x | x^2 - 4 = 0\}\)\(\newline\)Factor the quadratic equation.\(C = \{x | (x + 2)(x - 2) = 0\}\)\(\newline\)Set each factor equal to zero and solve for \(x\). \(x_1 = -2\), \(B = \{x | (x + 2)(x - 3) = 0\}\)\(0\), so \(B = \{x | (x + 2)(x - 3) = 0\}\)\(1\) a. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(2\)\(\newline\)Find the common elements between \(B = \{x | (x + 2)(x - 3) = 0\}\)\(3\) and \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\). \(B = \{x | (x + 2)(x - 3) = 0\}\)\(5\)\(\newline\)There are no common elements. b. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(6\)\(\newline\)Combine the sets. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(7\) \(B = \{x | (x + 2)(x - 3) = 0\}\)\(8\) c. \(B = \{x | (x + 2)(x - 3) = 0\}\)\(9\)\(\newline\)Find the common elements between \(x\)\(0\) and \(x\)\(1\). \(x\)\(2\) \(x\)\(3\) d. \(x\)\(4\)\(\newline\)Remove the elements of \(x\)\(1\) from \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\). \(x\)\(7\) e. \(x\)\(8\)\(\newline\)Remove the elements of \(B = \{x | (x + 2)(x - 3) = 0\}\)\(4\) from \(x\)\(1\). C - B = \{22\}

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