A wheel has 5 equally sized slices numbered from 1 to 5. Some are grey and some are white. The slices numbered 2 and 3 are grey. The slices numbered 1,4, and 5 are white. The wheel is spun and stops on a slice at random. Let X be the event that the wheel stops on a white slice, and let P(X) be the probability of X. Let 10 be the event that the wheel stops on a slice that is not white, and let 11 be the probability of 10. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column,EventOutcomesProbability123165(b) Subtract.18=
Q. A wheel has 5 equally sized slices numbered from 1 to 5. Some are grey and some are white. The slices numbered 2 and 3 are grey. The slices numbered 1,4, and 5 are white. The wheel is spun and stops on a slice at random. Let X be the event that the wheel stops on a white slice, and let P(X) be the probability of X. Let 10 be the event that the wheel stops on a slice that is not white, and let 11 be the probability of 10. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column,EventOutcomesProbability123165(b) Subtract.18=
Identify Outcomes for Event X: Identify the outcomes for event X (the wheel stops on a white slice). The white slices are numbered 1, 4, and 5.
Calculate Probability of X: Calculate the probability P(X) of the wheel stopping on a white slice. Since there are 3 white slices out of 5 total slices, the probability is 53.
Identify Outcomes for Event not X: Identify the outcomes for event not X (the wheel stops on a slice that is not white). The grey slices are numbered 2 and 3.
Calculate Probability of not X: Calculate the probability P(not X) of the wheel stopping on a grey slice. Since there are 2 grey slices out of 5 total slices, the probability is 52.
Subtract Probability from 1: Subtract the probability of not X from 1 to find 1−P(not X). Since P(not X) is 52, we have 1−52=55−52=53.