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A wheel has 55 equally sized slices numbered from 11 to 55. Some are grey and some are white. The slices numbered 22 and 33 are grey. The slices numbered 1,41,4, and 55 are white. The wheel is spun and stops on a slice at random. Let XX be the event that the wheel stops on a white slice, and let P(X)P(X) be the probability of XX. Let 1100 be the event that the wheel stops on a slice that is not white, and let 1111 be the probability of 1100. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column,\newline\newlineEvent\newlineOutcomes\newlineProbability\newline\newline11\newline22\newline33\newline1166\newline55\newline\newline\newline\newline\newline(b) Subtract.\newline1188=

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Q. A wheel has 55 equally sized slices numbered from 11 to 55. Some are grey and some are white. The slices numbered 22 and 33 are grey. The slices numbered 1,41,4, and 55 are white. The wheel is spun and stops on a slice at random. Let XX be the event that the wheel stops on a white slice, and let P(X)P(X) be the probability of XX. Let 1100 be the event that the wheel stops on a slice that is not white, and let 1111 be the probability of 1100. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column,\newline\newlineEvent\newlineOutcomes\newlineProbability\newline\newline11\newline22\newline33\newline1166\newline55\newline\newline\newline\newline\newline(b) Subtract.\newline1188=
  1. Identify Outcomes for Event X: Identify the outcomes for event X (the wheel stops on a white slice). The white slices are numbered 11, 44, and 55.
  2. Calculate Probability of X: Calculate the probability P(X)P(X) of the wheel stopping on a white slice. Since there are 33 white slices out of 55 total slices, the probability is 35\frac{3}{5}.
  3. Identify Outcomes for Event not XX: Identify the outcomes for event not XX (the wheel stops on a slice that is not white). The grey slices are numbered 22 and 33.
  4. Calculate Probability of not X: Calculate the probability P(not X)P(\text{not } X) of the wheel stopping on a grey slice. Since there are 22 grey slices out of 55 total slices, the probability is 25\frac{2}{5}.
  5. Subtract Probability from 11: Subtract the probability of not XX from 11 to find 1P(not X)1 - P(\text{not } X). Since P(not X)P(\text{not } X) is 25\frac{2}{5}, we have 125=5525=351 - \frac{2}{5} = \frac{5}{5} - \frac{2}{5} = \frac{3}{5}.

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