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A weight is attached to the end of a spring. Its height after 
t seconds is given by the equation

h(t)=5-2sin((2pi(t+1))/(7)).
When does the weight first reach its maximum height? Give an exact answer.
When 
t= seconds

A weight is attached to the end of a spring. Its height after t t seconds is given by the equation\newlineh(t)=52sin(2π(t+1)7). h(t)=5-2 \sin \left(\frac{2 \pi(t+1)}{7}\right) . \newlineWhen does the weight first reach its maximum height? Give an exact answer.\newlineWhen t= t= \square seconds

Full solution

Q. A weight is attached to the end of a spring. Its height after t t seconds is given by the equation\newlineh(t)=52sin(2π(t+1)7). h(t)=5-2 \sin \left(\frac{2 \pi(t+1)}{7}\right) . \newlineWhen does the weight first reach its maximum height? Give an exact answer.\newlineWhen t= t= \square seconds
  1. Find Maximum Height: The maximum height is reached when the sine function is at its maximum value, which is 11.
  2. Find Value of t: We need to find the value of tt for which sin(2π(t+1)7)\sin\left(\frac{2\pi(t+1)}{7}\right) equals 11.
  3. Set Sine Function Equal: Set the inside of the sine function equal to π/2\pi/2, because sin(π/2)=1\sin(\pi/2) = 1.
  4. Solve for tt: 2π(t+1)7=π2\frac{2\pi(t+1)}{7} = \frac{\pi}{2}. Now solve for tt.
  5. Multiply by 77: Multiply both sides by 77 to get rid of the denominator: 2π(t+1)=7π22\pi(t+1) = \frac{7\pi}{2}.
  6. Divide by 22π\pi: Divide both sides by 22π\pi to solve for (t+1)(t+1): t+1=7π4πt+1 = \frac{7\pi}{4\pi}.
  7. Simplify Right Side: Simplify the right side: t+1=74t+1 = \frac{7}{4}.
  8. Subtract 11: Subtract 11 from both sides to solve for tt: t=741t = \frac{7}{4} - 1.
  9. Convert to Common Denominator: Convert 11 to 44\frac{4}{4} to have a common denominator: t=7444.t = \frac{7}{4} - \frac{4}{4}.
  10. Add Fractions: Add the fractions: t=744t = \frac{7-4}{4}.
  11. Calculate Result: Calculate the result: t=34t = \frac{3}{4}.

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