Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

A waitress sold 18 ribeye steak dinners and 22 grilled salmon dinners, totaling 
$579.15 on a particular day. Another day she sold 29 ribeye steak dinners and 11 grilled salmon dinners, totaling 
$583.96. How much did each type of dinner cost?
The cost of ribeye steak dinners is 
$◻ and the cost of salmon dinners is 
$◻.
(Simplify your answer. Round to the nearest hundredth as needed.)

A waitress sold 1818 ribeye steak dinners and 2222 grilled salmon dinners, totaling $579.15 \$ 579.15 on a particular day. Another day she sold 2929 ribeye steak dinners and 1111 grilled salmon dinners, totaling $583.96 \$ 583.96 . How much did each type of dinner cost?\newlineThe cost of ribeye steak dinners is $ \$ \square and the cost of salmon dinners is $ \$ \square .\newline(Simplify your answer. Round to the nearest hundredth as needed.)

Full solution

Q. A waitress sold 1818 ribeye steak dinners and 2222 grilled salmon dinners, totaling $579.15 \$ 579.15 on a particular day. Another day she sold 2929 ribeye steak dinners and 1111 grilled salmon dinners, totaling $583.96 \$ 583.96 . How much did each type of dinner cost?\newlineThe cost of ribeye steak dinners is $ \$ \square and the cost of salmon dinners is $ \$ \square .\newline(Simplify your answer. Round to the nearest hundredth as needed.)
  1. Set up equations: Let RR be the cost of a ribeye steak dinner and SS be the cost of a grilled salmon dinner. We can set up two equations based on the information given: 18R+22S=579.1518R + 22S = 579.15 and 29R+11S=583.9629R + 11S = 583.96.
  2. Write first equation: Write the first equation from the given information: 18R+22S=579.1518R + 22S = 579.15.
  3. Write second equation: Write the second equation from the given information: 29R+11S=583.9629R + 11S = 583.96.
  4. Eliminate variable: Multiply the first equation by 1111 and the second equation by 2222 to eliminate SS when we subtract the equations. So we get 198R+242S=6370.65198R + 242S = 6370.65 and 638R+242S=12847.12638R + 242S = 12847.12.
  5. Solve for R: Subtract the second equation from the first to find RR: 198R+242S(638R+242S)=6370.6512847.12198R + 242S - (638R + 242S) = 6370.65 - 12847.12. This simplifies to 440R=6476.47-440R = -6476.47.
  6. Plug in R: Divide both sides by 440-440 to solve for RR: R=6476.47/440R = -6476.47 / -440. This gives us R=14.71925R = 14.71925.
  7. Solve for S: Now plug the value of RR back into the first equation to solve for SS: 18(14.71925)+22S=579.1518(14.71925) + 22S = 579.15. This simplifies to 264.9465+22S=579.15264.9465 + 22S = 579.15.
  8. Subtract values: Subtract 264.9465264.9465 from both sides to solve for SS: 22S=579.15264.946522S = 579.15 - 264.9465. This gives us 22S=314.203522S = 314.2035.
  9. Find SS: Divide both sides by 2222 to find SS: S=314.203522S = \frac{314.2035}{22}. This gives us S=14.28197727S = 14.28197727.
  10. Round to nearest hundredth: Round RR and SS to the nearest hundredth: R=$14.72R = \$14.72 and S=$14.28S = \$14.28.

More problems from Multi-step word problems