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A vegetable stand sells 
p pumpkins for 
$5.00 each and 
s squashes for 
$3.00 each. On Monday, the stand sold 6 more squashes than pumpkins and made a total of 
$98.00. Which system of equations can be used to determine the number of pumpkins and squashes sold?
Choose 1 answer:
(A) 
3p+5s=98

s=p+6
(B) 
3p+5s=98

p=s+6
(C) 
5p+3s=98

s=p+6
(D) 
5p+3s=98

p=s+6

A vegetable stand sells p p pumpkins for $5.00 \$ 5.00 each and s s squashes for $3.00 \$ 3.00 each. On Monday, the stand sold 66 more squashes than pumpkins and made a total of $98.00 \$ 98.00 . Which system of equations can be used to determine the number of pumpkins and squashes sold?\newlineChoose 11 answer:\newline(A) 3p+5s=98 3 p+5 s=98 \newlines=p+6 s=p+6 \newline(B) 3p+5s=98 3 p+5 s=98 \newlinep=s+6 p=s+6 \newline(C) 5p+3s=98 5 p+3 s=98 \newlines=p+6 s=p+6 \newline(D) 5p+3s=98 5 p+3 s=98 \newlinep=s+6 p=s+6

Full solution

Q. A vegetable stand sells p p pumpkins for $5.00 \$ 5.00 each and s s squashes for $3.00 \$ 3.00 each. On Monday, the stand sold 66 more squashes than pumpkins and made a total of $98.00 \$ 98.00 . Which system of equations can be used to determine the number of pumpkins and squashes sold?\newlineChoose 11 answer:\newline(A) 3p+5s=98 3 p+5 s=98 \newlines=p+6 s=p+6 \newline(B) 3p+5s=98 3 p+5 s=98 \newlinep=s+6 p=s+6 \newline(C) 5p+3s=98 5 p+3 s=98 \newlines=p+6 s=p+6 \newline(D) 5p+3s=98 5 p+3 s=98 \newlinep=s+6 p=s+6
  1. Identify Equations: question_prompt: What system of equations can be used to determine the number of pumpkins ( extit{p}) and squashes ( extit{s}) sold if the stand sold 66 more squashes than pumpkins and made a total of $98.00\$98.00?
  2. Write Total Money Equation: Step 11: Let's write the equation for the total money made from selling pumpkins and squashes. Pumpkins cost $5\$5 each, and squashes cost $3\$3 each. So, the equation is:\newline5p+3s=985p + 3s = 98
  3. Establish Relationship Equation: Step 22: Now, we know that the stand sold 66 more squashes than pumpkins. So, the equation for the relationship between the number of squashes and pumpkins sold is:\newlines=p+6s = p + 6
  4. Compare with Options: Step 33: We need to check which answer choice matches our equations. Let's look at the options:\newline(A) 3p+5s=983p + 5s = 98, s=p+6s = p + 6\newline(B) 3p+5s=983p + 5s = 98, p=s+6p = s + 6\newline(C) 5p+3s=985p + 3s = 98, s=p+6s = p + 6\newline(D) 5p+3s=985p + 3s = 98, $p = s + \(6\)
  5. Compare with Options: Step \(3\): We need to check which answer choice matches our equations. Let's look at the options:\(\newline\)(A) \(3p + 5s = 98\), \(s = p + 6\)\(\newline\)(B) \(3p + 5s = 98\), \(p = s + 6\)\(\newline\)(C) \(5p + 3s = 98\), \(s = p + 6\)\(\newline\)(D) \(5p + 3s = 98\), \(p = s + 6\) Step \(4\): By comparing the equations we wrote with the options, we can see that option (C) has the same equations as we derived:\(\newline\)\(5p + 3s = 98\), \(s = p + 6\)

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