A technology company is going to issue new ID codes to its employees. Each code will have two letters, followed by one digit, followed by one letter. The letters D,G, and Z and the digit 8 will not be used. So, there are 23 letters and 9 digits that will be used. Assume that the letters can be repeated. How many employee ID codes can be generated?
Q. A technology company is going to issue new ID codes to its employees. Each code will have two letters, followed by one digit, followed by one letter. The letters D,G, and Z and the digit 8 will not be used. So, there are 23 letters and 9 digits that will be used. Assume that the letters can be repeated. How many employee ID codes can be generated?
Calculate Available Characters: Calculate the number of available letters and digits for the ID codes. Since D, G, and Z are not used, there are 26−3=23 letters available. The digit 8 is not used, so there are 10−1=9 digits available.
Calculate Combinations for First Letter: Each ID code consists of two letters, followed by one digit, followed by one letter. Calculate the total number of combinations for the first letter. There are 23 choices for the first letter.
Calculate Combinations for Second Letter: Calculate the total number of combinations for the second letter. Since letters can be repeated, there are again 23 choices for the second letter.
Calculate Combinations for Digit: Calculate the total number of combinations for the digit. There are 9 choices for the digit.
Calculate Combinations for Third Letter: Calculate the total number of combinations for the third letter. There are 23 choices for the third letter.
Multiply Choices for Unique ID Codes: Multiply the number of choices for each part of the ID code to find the total number of unique ID codes. The calculation is 23 (first letter) ×23 (second letter) ×9 (digit) ×23 (third letter).
Perform Multiplication: Perform the multiplication: 23×23×9×23=105,879.