A scientist measures the initial amount of Carbon−14 in a substance to be 25 grams.The relationship between A, the amount of Carbon−14 remaining in that substance, in grams, and t, the elapsed time, in years, since the initial measurement is modeled by the following equation.A=25e−0.00012tIn how many years will the substance contain exactly 20 grams (g) of Carbon14 ?Give an exact answer expressed as a natural logarithm.years
Q. A scientist measures the initial amount of Carbon−14 in a substance to be 25 grams.The relationship between A, the amount of Carbon−14 remaining in that substance, in grams, and t, the elapsed time, in years, since the initial measurement is modeled by the following equation.A=25e−0.00012tIn how many years will the substance contain exactly 20 grams (g) of Carbon14 ?Give an exact answer expressed as a natural logarithm.years
Write Given Exponential Decay Equation: Write down the given exponential decay equation.The equation provided is A=25e(−0.00012t), where A is the amount of Carbon−14 remaining and t is the time in years.
Set A Equal to 20 Grams: Set A equal to 20 grams to solve for t. We want to find out when the substance will contain exactly 20 grams of Carbon−14, so we set A to 20. 20=25e−0.00012t
Divide by 25 to Isolate Exponential Term: Divide both sides of the equation by 25 to isolate the exponential term.(20/25)=e(−0.00012t)0.8=e(−0.00012t)
Take Natural Logarithm to Solve for t: Take the natural logarithm of both sides to solve for t.ln(0.8)=ln(e−0.00012t)
Simplify Right Side of Equation: Use the property of logarithms that ln(ex)=x to simplify the right side of the equation.ln(0.8)=−0.00012t
Divide by −0.00012 to Solve for t: Divide both sides by −0.00012 to solve for t.t=−0.00012ln(0.8)
Leave Answer as Natural Logarithm: Leave the answer as a natural logarithm as requested.The final answer is expressed as a natural logarithm.
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