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$A right triangular prism is shown at the right. The bases are isosceles triangles. a) Find the volume of the prism. b) A plane slices the prism, as shown, parallel to the bases. Find the area of the cross section created by the slice. c) Find the surface area of the prism to the nearest square inch. Given a cube, with vertices as labeled, and with a lateral side length of 10cm. a) Find the measure of /_FBH : b) Find the area of /_\FBH in square centimeters. c) Find the volume of the cube in cubic centimeters.$

$1$ . A right triangular prism is shown at the right. The bases are isosceles triangles. $\newline$ a) Find the volume of the prism. $\newline$ b) A plane slices the prism, as shown, parallel to the bases. Find the area of the cross section created by the slice. $\newline$ c) Find the surface area of the prism to the nearest square inch. $\newline$ $2$ . Given a cube, with vertices as labeled, and with a lateral side length of $10 \mathrm{~cm}$ . $\newline$ a) Find the measure of $\angle F B H$ : $\newline$ b) Find the area of $\triangle F B H$ in square centimeters. $\newline$ c) Find the volume of the cube in cubic centimeters.

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Area of quadrilaterals and triangles: word problems

Full solution

Q.

1

. A right triangular prism is shown at the right. The bases are isosceles triangles.

\newline

a) Find the volume of the prism.

\newline

b) A plane slices the prism, as shown, parallel to the bases. Find the area of the cross section created by the slice.

\newline

c) Find the surface area of the prism to the nearest square inch.

\newline

2

. Given a cube, with vertices as labeled, and with a lateral side length of

10 \mathrm{~cm}

.

\newline

a) Find the measure of

\angle F B H

:

\newline

b) Find the area of

\triangle F B H

in square centimeters.

\newline

c) Find the volume of the cube in cubic centimeters.

Calculate total tape needed: Calculate the total amount of tape needed and the amount per roll to find the number of rolls required. $\newline$ Total tape needed = $8,000 \, \text{cm}$ , Tape per roll = $2,000 \, \text{cm}$ . $\newline$ $8,000 \, \text{cm} \div 2,000 \, \text{cm} = 4$ rolls.

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\newline

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