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A person invested $220\$220 in an account growing at a rate allowing the money to double every 1313 years. How much money would be in the account after 2727 years, to the nearest dollar?

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Q. A person invested $220\$220 in an account growing at a rate allowing the money to double every 1313 years. How much money would be in the account after 2727 years, to the nearest dollar?
  1. Identify amounts and period: Identify the initial amount, the total time, and the doubling period.\newlineInitial amount PP = $220\$220\newlineTotal time tt = 2727 years\newlineDoubling period dd = 1313 years
  2. Calculate number of periods: Calculate the number of doubling periods in 2727 years.\newlineNumber of doubling periods =Total timeDoubling period= \frac{\text{Total time}}{\text{Doubling period}}\newline=27 years13 years= \frac{27 \text{ years}}{13 \text{ years}}\newline=2.07692307692= 2.07692307692\newlineWe round this to 22 because the money doubles only at the end of each full period.

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