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A pedestrian underpass is constructed beneath a roadway using a cylindrical pipe with radius 1.8m. The bottom of the pipe will be filled and paved. The headroom at the centre of the path is 2.8m. How wide is the path? ake It Further A spherical fish bowl has diameter 26cm. The surface of the water in the bowl is a

A pedestrian underpass is constructed beneath a roadway using a cylindrical pipe with radius 1.8 m 1.8 \mathrm{~m} . The bottom of the pipe will be filled and paved. The headroom at the centre of the path is 2.8 m 2.8 \mathrm{~m} . How wide is the path?\newlineake It Further\newlineA spherical fish bowl has diameter 26 cm 26 \mathrm{~cm} . The surface of the water in the bowl is a

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Full solution

Q. A pedestrian underpass is constructed beneath a roadway using a cylindrical pipe with radius 1.8 m 1.8 \mathrm{~m} . The bottom of the pipe will be filled and paved. The headroom at the centre of the path is 2.8 m 2.8 \mathrm{~m} . How wide is the path?\newlineake It Further\newlineA spherical fish bowl has diameter 26 cm 26 \mathrm{~cm} . The surface of the water in the bowl is a
  1. Path Width Calculation: The path's width is the diameter of the part of the cylindrical pipe that is above the paved surface.
  2. Remaining Height Calculation: Given the headroom at the center is 2.8 m2.8\,\text{m}, we can calculate the remaining height of the pipe that is filled and paved as the radius minus the headroom: 1.8 m−2.8 m.1.8\,\text{m} - 2.8\,\text{m}.

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