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A particle moves along a lines so that at time t where 0 <= t <= pi its position is given by s(t)=-4cos t-(t^(2))/(2)+10. What is the velocity of the particle when its acceleration is zero? cos(t)-1 {:[s(t)=-4cos t-(t^(2))/(2)+10],[v(t)=4sin(t)-t],[0=4sin(t)-t],[t=2.4745768],[a(2.47)=4.14u//u]:}

33. A particle moves along a lines so that at time t t where 0≤t≤π 0 \leq t \leq \pi its position is given by s(t)=−4cos⁡t−t22+10 s(t)=-4 \cos t-\frac{t^{2}}{2}+10 . What is the velocity of the particle when its acceleration is zero?\newlinecos⁡(t)−1 \cos (t)-1 \newlines(t)=−4cos⁡t−t22+10v(t)=4sin⁡(t)−t0=4sin⁡(t)−tt=2.4745768a(2.47)=4.14u/u \begin{array}{l} s(t)=-4 \cos t-\frac{t^{2}}{2}+10 \\ v(t)=4 \sin (t)-t \\ 0=4 \sin (t)-t \\ t=2.4745768 \\ a(2.47)=4.14 \mathrm{u} / \mathrm{u} \end{array}

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Q. 33. A particle moves along a lines so that at time t t where 0≤t≤π 0 \leq t \leq \pi its position is given by s(t)=−4cos⁡t−t22+10 s(t)=-4 \cos t-\frac{t^{2}}{2}+10 . What is the velocity of the particle when its acceleration is zero?\newlinecos⁡(t)−1 \cos (t)-1 \newlines(t)=−4cos⁡t−t22+10v(t)=4sin⁡(t)−t0=4sin⁡(t)−tt=2.4745768a(2.47)=4.14u/u \begin{array}{l} s(t)=-4 \cos t-\frac{t^{2}}{2}+10 \\ v(t)=4 \sin (t)-t \\ 0=4 \sin (t)-t \\ t=2.4745768 \\ a(2.47)=4.14 \mathrm{u} / \mathrm{u} \end{array}
  1. Calculate rolls needed: Calculate the number of rolls needed by dividing the total amount of tape by the amount of tape on each roll. 8,000 cm÷2,000 cm/roll=4 rolls8,000 \, \text{cm} \div 2,000 \, \text{cm}/\text{roll} = 4 \, \text{rolls}
  2. Order tape rolls: So, the electrician should order 44 rolls of tape.

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