A natural number, N, is 4 less than another natural number, M. The sum of the reciprocals of M and N is 5 times the reciprocal of twice the value of M. What are the two numbers?
Q. A natural number, N, is 4 less than another natural number, M. The sum of the reciprocals of M and N is 5 times the reciprocal of twice the value of M. What are the two numbers?
Denote and Express: Let's denote the natural number M and express N in terms of M.N=M−4
Write Sum Equation: Now, let's write the equation for the sum of the reciprocals of M and N being 5 times the reciprocal of twice the value of M.M1+N1=2M5
Substitute and Simplify: Substitute N with M−4 in the equation.M1+M−41=2M5
Find Common Denominator: Find a common denominator for the left side of the equation.M(M−4)(M−4)+M=2M5
Clear Denominators: Simplify the numerator on the left side of the equation.(2M−4)/[M(M−4)]=5/(2M)
Expand Equation: Multiply both sides of the equation by 2M(M−4) to clear the denominators.2M(2M−4)=5M(M−4)
Set Equation to Zero: Expand both sides of the equation.4M2−8M=5M2−20M
Combine Like Terms: Move all terms to one side to set the equation to zero.5M2−4M2−20M+8M=0
Factor Out M: Combine like terms. M2−12M=0
Solve for M: Factor out M from the equation.M(M−12)=0
Find N: Set each factor equal to zero and solve for M.M=0 or M−12=0
Find N: Set each factor equal to zero and solve for M.M=0 or M−12=0Since M is a natural number, M cannot be 0. So we solve for the second factor.M=12
Find N: Set each factor equal to zero and solve for M.M=0 or M−12=0Since M is a natural number, M cannot be 0. So we solve for the second factor.M=12Now that we have the value of M, we can find N.N=M−4N=12−4M−12=00