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A monkey is swinging from a tree. On the first swing, she passes through an arc of 20m20\text{m}. With each swing, she passes through an arc 45\frac{4}{5} the length of the previous swing. What is the total distance the monkey has traveled when she completes her 10th10^{\text{th}} swing? Round your final answer to the nearest meter.

Full solution

Q. A monkey is swinging from a tree. On the first swing, she passes through an arc of 20m20\text{m}. With each swing, she passes through an arc 45\frac{4}{5} the length of the previous swing. What is the total distance the monkey has traveled when she completes her 10th10^{\text{th}} swing? Round your final answer to the nearest meter.
  1. Calculate distance using formula: Calculate the distance of each swing using the geometric sequence formula.\newlineFirst swing = 20m20m,\newlineSecond swing = (45)×20m=16m(\frac{4}{5}) \times 20m = 16m,\newlineThird swing = (45)×16m=12.8m(\frac{4}{5}) \times 16m = 12.8m, and so on.
  2. Use geometric series formula: Use the formula for the sum of a geometric series: Sn=a×(1rn)/(1r)S_n = a \times (1 - r^n) / (1 - r), where aa is the first term, rr is the common ratio, and nn is the number of terms.\newlineHere, a=20ma = 20\,\text{m}, r=45r = \frac{4}{5}, and n=10n = 10.\newlineS10=20×(1(45)10)/(145)S_{10} = 20 \times (1 - (\frac{4}{5})^{10}) / (1 - \frac{4}{5})
  3. Calculate (4/5)10(4/5)^{10}: Calculate (4/5)10(4/5)^{10} using a calculator.\newline(4/5)100.1074(4/5)^{10} \approx 0.1074
  4. Substitute into formula: Substitute back into the sum formula.\newlineS10=20×(10.1074)/(145)S_{10} = 20 \times (1 - 0.1074) / (1 - \frac{4}{5})\newlineS10=20×0.8926/0.2S_{10} = 20 \times 0.8926 / 0.2\newlineS10=89.26/0.2S_{10} = 89.26 / 0.2\newlineS10=446.3S_{10} = 446.3
  5. Round final answer: Round the final answer to the nearest meter.\newlineFinal distance 446\approx 446 meters.

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