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A line with slope -3 passes through the point (9,-20). Find an equation of the line. Use y to represent the dependent variable (output) and x to represent the independent variable (input). Your equation can be in any form.

A line with slope −3-3 passes through the point (9,−20) (9,-20) . Find an equation of the line. Use y y to represent the dependent variable (output) and x x to represent the independent variable (input). Your equation can be in any form.

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Write a linear equation from a slope and y-interceptright chevron icon

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Q. A line with slope −3-3 passes through the point (9,−20) (9,-20) . Find an equation of the line. Use y y to represent the dependent variable (output) and x x to represent the independent variable (input). Your equation can be in any form.
  1. Identify slope-intercept form: Identify the slope-intercept form of a line's equation. The slope-intercept form of a line's equation is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  2. Use point-slope form: Use the point-slope form to find the equation of the line. The point-slope form of a line's equation is y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line. We know the slope (mm) is −3-3 and the point (x1,y1)(x_1, y_1) is (9,−20)(9, -20).
  3. Substitute slope and coordinates: Substitute the slope and the coordinates of the point into the point-slope form.\newlineUsing the point (9,−20)(9, -20) and the slope −3-3, the equation becomes y−(−20)=−3(x−9)y - (-20) = -3(x - 9).
  4. Simplify the equation: Simplify the equation. y+20=−3x+27y + 20 = -3x + 27 (distributing the −3-3 to both xx and −9-9)
  5. Isolate y: Isolate y to get the equation in slope-intercept form.\newliney=−3x+27−20y = -3x + 27 - 20\newliney=−3x+7y = -3x + 7

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