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A line that includes the point (−6,−1)(-6,-1) has a slope of 13\frac{1}{3}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line that includes the point (−6,−1)(-6,-1) has a slope of 13\frac{1}{3}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form is given by the equation y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Point and Slope: Substitute the given point and slope into the point-slope form.\newlineWe have the point (−6,−1)(-6, -1) and the slope 13\frac{1}{3}. Substituting these values into the point-slope form, we get:\newliney−(−1)=(13)(x−(−6))y - (-1) = \left(\frac{1}{3}\right)(x - (-6))
  3. Simplify Equation: Simplify the equation.\newlineSimplifying the equation, we get:\newliney+1=13(x+6)y + 1 = \frac{1}{3}(x + 6)\newlineThis is the equation of the line in point-slope form.

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