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A line that includes the point (4,6)(4,-6) has a slope of 15-\frac{1}{5}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newlineyy - ______= = ______(x(x - ______))

Full solution

Q. A line that includes the point (4,6)(4,-6) has a slope of 15-\frac{1}{5}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newlineyy - ______= = ______(x(x - ______))
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form: yy1=m(xx1)y - y_1 = m(x - x_1)
  2. Given Point and Slope: We have:\newlinePoint: (4,6)(4, -6)\newlineSlope: 15-\frac{1}{5}\newlineWhat is the point-slope form of the line?\newlineSubstitute 15-\frac{1}{5} for mm, 44 for x1x_1, and 6-6 for y1y_1 in point-slope form.\newliney(6)=(15)(x4)y - (-6) = (-\frac{1}{5})(x - 4)
  3. Substitute Values: Simplify the equation by removing the parentheses around 6-6.\newliney+6=(15)(x4)y + 6 = \left(-\frac{1}{5}\right)(x - 4)

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