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A line passes through the points (2,16)(-2, -16) and (4,20)(4 ,20). Write its equation in slope-intercept form.

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Q. A line passes through the points (2,16)(-2, -16) and (4,20)(4 ,20). Write its equation in slope-intercept form.
  1. Calculate slope: Step 11: Calculate the slope of the line using the given points (2,16)(-2, -16) and (4,20)(4, 20).\newlineSlope formula: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}\newlinem=20(16)4(2)m = \frac{20 - (-16)}{4 - (-2)}\newlinem=366m = \frac{36}{6}\newlinem=6m = 6
  2. Find y-intercept: Step 22: Use the slope and one of the points to find the y-intercept, bb. Let's use point (4,20)(4, 20).\newlineEquation form: y=mx+by = mx + b\newlineSubstitute m=6m = 6, x=4x = 4, and y=20y = 20.\newline20=6(4)+b20 = 6(4) + b\newline20=24+b20 = 24 + b\newlineb=2024b = 20 - 24\newlineb=4b = -4
  3. Write equation: Step 33: Write the equation of the line in slope-intercept form using the values of mm and bb.\newlineEquation: y=mx+by = mx + b\newlineSubstitute m=6m = 6 and b=4b = -4.\newliney=6x4y = 6x - 4

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