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A line has a slope of 12\frac{1}{2} and passes through the point (2,−1)(2,-1). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)

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Point-slope form: write an equationright chevron icon

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Q. A line has a slope of 12\frac{1}{2} and passes through the point (2,−1)(2,-1). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by the formula y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form.\newlineWe are given the slope m=12m = \frac{1}{2} and the point (2,−1)(2, -1). Substituting these values into the point-slope form, we get y−(−1)=(12)(x−2)y - (-1) = \left(\frac{1}{2}\right)(x - 2).
  3. Simplify Equation: Simplify the equation.\newlineSimplifying the left side of the equation by removing the parentheses around −1-1, we get y+1=(12)(x−2)y + 1 = \left(\frac{1}{2}\right)(x - 2).

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